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2 years ago

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Morgan uses 1/4 of her supply of raisins to make trail mix and 3/8 of her supply of raisins to make cookies. If Morgan uses 5 po

unds of raisins, how many pounds of raisins are in her supply?

1 answer:

Mnenie [13.5K]2 years ago

5 0

First, we have to find how much supply of raisins she uses. It is 1/4+3/8=5/8. It makes the total 5 pounds of raisins that she uses. Constructing an equation, we can find how much raisins are available in her supply. $\frac{5}{8} x = 5$ . And the x= 8.

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Semielliptical Arch Bridge An arch for a bridge over a highway is in the form of half an ellipse. The top of the arch is 20 feet

photoshop1234 [79]

Answer:

the span of the bridge is 73.7 feet

Step-by-step explanation:

The equation of an ellipse with a vertical major axis(i.e major axis parallel to y axis) is given by:

$\frac{(x-h)^{2} }{b^{2} } + \frac{(y-k)^{2} }{a^{2} }= 1$ a>b

where (h,k) are the coordinates of the center of the ellipse, a is the length of the major axis and b is the length of the minor axis

For this problem, the center of the ellipse (h,k) = (0,0)

Therefore:

$\frac{(x)^{2} }{b^{2} } + \frac{(y)^{2} }{a^{2} }= 1$

The top of the arch is 20 feet above the ground level (the major axis), therefore a=20

length of the major axis = 2a= 2*20 = 40

$\frac{x^{2} }{b^{2} } + \frac{y^{2} }{20^{2} }= 1\\\frac{x^{2} }{b^{2} } + \frac{y^{2} }{400 }= 1$

The coordinates of the ellipse (x,y) = (28,13)

$\frac{28^{2} }{b^{2} } + \frac{13^{2} }{400 }= 1$

$\frac{28^{2} }{b^{2} } + 0.4225= 1$

$\frac{784 }{b^{2} } = 0.5775$

b² ≅ 1358

b≅36.85

Length of minor axis (2b) = 73.7 feet.

the span of the bridge is 73.7 feet

7 0

2 years ago

four friends contributed the sum of money to a charitable organization in the ratio 1:3:5:7. if the largest amount contrebuted i

suter [353]

9514 1404 393

Answer:

birr 80

Step-by-step explanation:

The total number of ratio units is 1+3+5+7 = 16. The largest amount is represented by 7 ratio units, so is 7/16 of the total. The total contributed is ...

16/7 × (birr 35) = birr 80

3 0

2 years ago

find the scale, k, of H(3,4) if H'(9,12) after going through the transformation (x,y) ---> (kx,ky) centered at the origin

stiks02 [169]

The value of scale k is 3

Step-by-step explanation:

In order to find the scale , we can either divide the coordinates of H' by the original point or compare both the points to find the original ordered pair.

Given

H(3,4)

H'(9,12)

The coordinates of H are multiplied with some integer k to form H'

So,

<u>For x-coordinate:</u>

3k = 9

k = 9/3 = 3

<u>For y-coordinate:</u>

4k = 12

k = 12/4 = 3

Hence,

The value of scale k is 3

Keywords: Coordinate geometry, scaling

Learn more about scaling at:

#LearnwithBrainly

5 0

2 years ago

A survey of the men in a certain town showed that 35% of the men have blond hair and 14% of them have blond hair and blue eyes.

natita [175]

If you are given he has blond hair, so the total probability will be 35%. And among them, he needs to have blue eyes, its probability is 14% among the 35%. So the final probability is 14%/35%=40%.

7 0

2 years ago

According to a survey, 10% of Americans are afraid to fly. Suppose 1100 Americans are sampled. a) What is the probability that 1

JulijaS [17]

Answer:

a) 14.46%

b) 0.00%

c) 1.54%

Step-by-step explanation:

According to the survey, 10% of Americans are afraid to fly.

This means $p=0.10$ and $q=1-0.10=0.90$ .

If 1100 Americans are sampled, then the sample size is $n=1100$ .

The mean of the distribution is $\mu=np$ .

This means $\mu=1100\times 0.10=110$

The standard deviation is $\sigma=\sqrt{npq}$

We substitute the values to get:

$\sigma=\sqrt{1100\times 0.1\times 0.9}=9.95$

a) We want to find the probability that 121 or more Americans in the survey are afraid to fly.

We first apply the continuity correction factor to get: $P(X\ge121)=P(X\:>\:121-0.5)\\P(X\ge121)=P(X\:>\:120.5)$

We now convert to Z-scores to get:

$P(X\:>\:120.5)=P(z\:>\:\frac{120.5-110}{9.95})=1.06\\$

From the standard normal distribution table P(z>1.06)=0.1446

As a percentage, the probability is 14.46%

b) We want to find the probability that 165 or more Americans in the survey are afraid to fly.

We apply the CCF to get:

$P(X\ge165)=P(X\:>\:165-0.5)\\P(X\ge165)=P(X\:>\:164.5)$

We convert to z-scores:

$P(X\:>\:164.5)=P(z\:>\:\frac{164.5-110}{9.95})=5.48$

From the normal distribution, P(z>164.5)=0

c) First, 8% of 1100 is 88.

We want to find the probability that 88 or less Americans in the survey are afraid to fly.

We apply the CCF to get:

$P(X\le88)=P(X\:$

We convert to z-scores:

$P(X\:$

From the normal distribution, P(z>\:-2.16)=0.0154

As a percentage, we get 1.54%

3 0

2 years ago