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Simora [160]
1 year ago
13

(Please this is URGENT!) On a computer screen, Jennifer just created a triangular design of a banner with vertices at A(-4,3), B

(-1,5) and C(-1,2). She can use the computer software to perform transformations on this design.
Which sequence of two transformations could she perform so that the transformed vertices become A'(4,-5), B'(7,-7), and C'(7,-4)?


a. translating 6 units down, followed by translating 8 units to the right

b. reflecting about the line y = -2, followed by translating 8 units to the right

c. reflecting about the line y = -1, followed by reflecting about the y-axis

d. reflecting about the line y = -1, followed by translating 8 units to the right
Mathematics
2 answers:
boyakko [2]1 year ago
7 0

Answer:

The correct option is;

d. Reflecting about the line y = -1, followed by translating 8 units to the right

Step-by-step explanation:

The coordinates of the vertices of the banner Jane created = A(-4, 3), B(-1, 5) and C(-1, 2)

By reflecting across the line y = -1, we get

A(-4, 3) by reflection across the line y = -1 gives A(-4, -5)

B(-1, 5) by reflection across the line y = -1 gives B(-1, -7)

C(-1, 2) by reflection across the line y = -1 gives C(-1, -4)

By translating 8 units to the right get

A(-4, 3) by translation 8 units right gives A prime (4, -5)

B(-1, 5) by translation 8 units right gives B prime (7, -7)

C(-1, 2) by translation 8 units right gives C prime (7, -4)

Therefore, the two transformation that she could perform so that the transformed vertices become A prime (4, -5), B prime (7, -7), and C prime (7, -4) are;

1) Reflection across the line y = -1

2) An horizontal translation 8 units to the right get.

Luba_88 [7]1 year ago
4 0

Answer:

D

Step-by-step explanation:

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Josephine bought 8 packets of biscuits. Each packet had a mass of 500 g
Nataly_w [17]

Answer: 985 g

Step-by-step explanation:

Total mass = 8 × 500g = 4000g

Let the three new packs be X, Y, and Z, for first, second, and third pack respectively.

4000g = X + Y + Z

let's put X and Z in terms of Y, since we're trying to solve for the second pack.

X = 2Y, and Z = Y + 60

Therefore,

4000 = X + Y + Z

4000 = 2Y + Y +Y + 60

4000 = 4Y +60

4000 - 60 = 4Y

3940 = 4Y

3940 ÷ 4 = Y

985g = Y = mass of the second pack

7 0
2 years ago
The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po
Leona [35]

Answer:

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

Step-by-step explanation:

Data given

Campus   Sample size     Mean    Population deviation

   1                 330               33                      8

   2                310                31                       7

\bar X_{1}=33 represent the mean for sample 1  

\bar X_{2}=31 represent the mean for sample 2  

\sigma_{1}=8 represent the population standard deviation for 1  

\sigma_{2}=7 represent the population standard deviation for 2  

n_{1}=330 sample size for the group 1  

n_{2}=310 sample size for the group 2  

\alpha Significance level provided  

z would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:  

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

P value  

Since is a one right tailed test the p value would be:  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

5 0
2 years ago
a car travels 30 1/2 miles in 2/3 of an hour. what is the average speed, in miles per hour, of the car ?
Contact [7]

Answer:

speed=225.75 miles per hour

Step-by-step explanation:

given:

s=301/2

t=2/3

we have,

v=s/t

v=(301/2)/(2/3)

=(301/2)×3/2

=903/4

v=225.75

therefore, speed of car will be 225.75 miles per hour

6 0
1 year ago
7.9-3.47=please show me how to rewrite it vertically?
Lemur [1.5K]

Answer:

4.43

Step-by-step explanation:

7.90

- 3.47

__________

4. 4 3

I couldn't regroup but of you cross out 0 and put 10, 10-7= 3

and you have to borrow one from 9 and make it 8 and 8-4=4

4 0
2 years ago
A laser pointer in the shape of a cylinder is 13 centimeters long with a radius of 1 centimeter. On top it has a cone-shaped tip
bezimeni [28]
We know that

step 1
find the volume of a cylinder

volume of a cylinder=pi*r²*h
where
h=13 cm
r=1 cm
volume of a cylinder=pi*1²*13----> 13*pi cm³

step 2
find the volume of a cone

volume of a cone=(1/3)*pi*r²*h
where
r=1 cm
h=3 cm
volume of a cone=(1/3)*pi*1²*3-----> pi cm³

step 3
find the volume of the laser pointer

volume of the laser pointer=volume of a cylinder+volume of a cone
volume of the laser pointer=13*pi+pi-----> 14*pi cm³

the answer is
volume of the laser pointer is 14*pi cm³
4 0
2 years ago
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