Answer:
Step-by-step explanation:
Lines m and l are the parallel lines and a line 'n' is a transverse intersecting these lines.
m∠2 = 50°
m∠1 + m∠2 = 180° [Linear pair of angles]
m∠1 = 180° - 50°
m∠1 = 130°
m∠3 = m∠1 = 130° [Vertically opposite angles]
m∠3 + m∠5 = 180° [Consecutive interior angles]
m∠5 = 180° - m∠3
= 180° - 130°
= 50°
m∠6 + m∠5 = 180° [Linear pair of angles]
m∠6 = 180° - 50° = 130°
Answer:
The triangle is an obtuse scalene triangle
Step-by-step explanation:
we know that
if 
--------> is a right triangle
if 
--------> is an obtuse triangle
if 
--------> is an acute triangle
where
c is the greater side
we have
so
so
-------> is an obtuse triangle
Remember that
The given triangle has three different length side
so
Is a scalene triangle
therefore
The triangle is an obtuse scalene triangle
Answer:
x = StartFraction negative
(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction
Step-by-step explanation:
0 = – 3x2 – 2x + 6
It can still be written as
– 3x2 – 2x + 6 =0
Quadratic formula=
-b+or-√b^2-4ac/2a
Where
a=-3
b=-2
c=6
x= -(-2)+ or-√(-2)^2-4(-3)(6)/2(-3)
x = StartFraction negative
(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction
We have the following dimensions:
w=wide
w+70=length
We have a right triangle:
leg₁=w
leg₂=w+70
hypotenuse=130
Pythagoras theorem:
leg₁²+leg₂²=hypotenuse²
Then:
w²+(w+70)²=130²
We have to solve that equation:
w²+(w+70)²=130²
w²+w²+140w+4900=16900
2w²+140w+4900-16900=0
2w²+140w-12000=0
(2w²+140w-12000)/2=0/2
w²+70w-6000=0
w=(-70⁺₋√(4900+24000)) / 2
=(-70⁺₋170) / 2
We have two possible solutions:
Solution 1
w=(-70-170)/2=-120 (this solution is not possible because the result is negative and it have no sense in this problem).
Solution 2
w=(-70+170)/2=50 (this is the right solution)
w=50
w+70=120
ANSWER: the length would be 120 u (u=units of length ) and the wide would be 50 u.
