We have to choose the correct answer for the center of the circumscribed circle of a triangle. The center of the circumscribed circle of a triangle is where the perpendicular bisectors of a triangle intersects. In this case P1P2 and Q1Q2 are perpendicular bisectors of sides AB and BC, respectively and they intersect at point P. S is the point where the angle bisectors intersect ( it is the center of the inscribed circle ). Answer: <span>P.</span>
1. To translate to the left, add to x.
The equation is: y = |x + 2|
2. To translate down, add to y.
The equation is: y + 2 = |x| OR y = |x| - 2 (subtract 2 from each side)
Hope this helps!
Answer:
The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph
Step-by-step explanation:
we know that
The speed is equal to divide the distance by the time
Let
x -----> the speed of the wind in miles per hour
y ----> the speed of the jet in still air in miles per hour
we know that
<em>With a tailwind</em>

----> equation A
<em>With a headwind</em>

----> equation B
solve the system of equations A and B by elimination
Adds equation A and equation B

<em>Find the value of x</em>



therefore
The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph
Answer:
A) 
B) 
C) for n = 2
= 1
for n = 3
= 3
for n = 4
= 8
for n = 5
= 19
Step-by-step explanation:
A) A recurrence relation for the number of bit strings of length n that contain a pair of consecutive Os can be represented below
if a string (n ) ends with 00 for n-2 positions there are a pair of consecutive Os therefore there will be :
strings
therefore for n ≥ 2
The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os
b ) The initial conditions
The initial conditions are : 
C) The number of bit strings of length seven containing two consecutive 0s
here we apply the re occurrence relation and the initial conditions
for n = 2
= 1
for n = 3
= 3
for n = 4
= 8
for n = 5
= 19