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mel-nik [20]
1 year ago
9

Brahmagupta solved a quadratic equation of the form ax2 + bx = c using the formula x =, which involved only one solution. Using

Brahmagupta’s method, the solution to the quadratic equation x2 + 7x = 8 would be x = 1. Using modern methods, the first step in solving the quadratic equation x2 + 7x = 8 would be to put it in standard form by . What is the second solution?
Mathematics
2 answers:
weeeeeb [17]1 year ago
4 0
X2+7x-8=0
product=-8 times 1 = -8
sum= 7
{-1, 8}
x2-1x+8x-8=0
x(x-1)+8(x-1)=0
x+8=0 or X-1=0
x=-8
RideAnS [48]1 year ago
4 0

Answer:

First part- subtracting 8 from both sides

Second part- x=-8

Step-by-step explanation:

edg 2020

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Use the distributive property to solve the equation 4x/5-x=x/10-9/2
Oksana_A [137]

Answer:

\Huge\boxed {x = 15}

Step-by-step explanation:

⟾Collect like terms

  • 8x - 10x = x - 45

⟾Move the variable to the left

  • - 2x = x - 45

⟾Collect like terms again

  • - 2x - x = - 45

⟾Divide both sides by -3

  • - 3x = - 45

⟾ x = 45 ÷ 3

  • x = 15.

Hope it's helps you

4 0
2 years ago
Find the volume of a right circular cone that has a height of 12.7 m and a base with a circumference of 18.9 m. Round your answe
DochEvi [55]

Step-by-step explanation:

We have,

Height of cone, h = 12.7 m

Circumference of base, C = 18.9 m

The base of a circular cone is circular. The circumference of circle is given by :

C=2\pi r

r is radius

r=\dfrac{C}{2\pi}\\\\r=\dfrac{18.9 }{2\pi}\\\\r=3\ m

The volume of a right circular cone is given by the formula as :

V=\dfrac{1}{3}\pi r^2h

V=\dfrac{1}{3}\times 3.14 \times 3^2\times 12.7\\\\V=119.634\ m^3

7 0
2 years ago
If week 1=5, week 2=3, week 3=7, week 4=5 what will week 5 be?
olga2289 [7]

Answer: 11

Step-by-step explanation:

The sequence goes +4, +1, +5, +1... so obviously the next number will be +6. So, 5+6=11

The answer is week 5=11

4 0
1 year ago
Which is the additive inverse of the complex number -8+3i?
lawyer [7]
The additive inverse of a complex z is a complex number -z, so that

\mathsf{z+(-z)=-z+z=0+0i=0}


Finding -z:

\mathsf{z=-8+3i}\\\\\\ \mathsf{z+(-z)=0+0i}\\\\\ \mathsf{-8+3i+(-z)=0+0i}\\\\ \mathsf{-z=0+0i+8-3i}\\\\ \mathsf{-z=(0+8)+(0i-3i)}\\\\ \boxed{\begin{array}{c}\mathsf{-z=8-3i} \end{array}}\qquad\checkmark


If you're having problems understanding this answer, try seeing it through your browser: <span>brainly.com/question/2159647


</span>I hope this helps.


Tags: <em>complex number additive inverse opposite algebra</em>

3 0
2 years ago
Hiromi sells 12 T-shirts each week at a price of $13.00. Past sales have shown that for every $0.25 decrease in price, 4 more T-
Lerok [7]
(13-0.25x4)(12+4x4)=2,464
(13-0.25x5)(12+4x5)=3,845
(13-0.25x6)(12+4x6)=2,845
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4 0
2 years ago
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