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jekas [21]
1 year ago
11

Now Cathy is three times as old as Katie. In six years Cathy will be only twice as old as Katie. How old is each girl now?

Mathematics
1 answer:
klasskru [66]1 year ago
5 0

Answer:

6 and 18

6+6=12

18+6=24

12x2=24

Unless a number is given it is mainly trial and error so guessing numbers that fit the first part of Ax3=B

Step-by-step explanation:

You might be interested in
Bruce's speed when swimming in still water is 5 meters/second. He is swimming in a direction 25° east of north. The current is m
Vsevolod [243]

Answer:

<2.1130913087, 4.53153893518>;  <−3.03108891325, −1.75>; <−0.91799760455, 2.78153893518>

Step-by-step explanation:

Bruce's vector is <5cos(90-25), 5sin(90-25)> = <5cos(65), 5sin(65)> ≈ <2.1130913087, 4.53153893518>

The wind's vector is <3.5cos(270-60), 3.5sin(270-60)> = <3.5cos(210), 3.5sin(210)>  ≈ <−3.03108891325, −1.75>

You add them together to find his actual motion:

<−0.91799760455, 2.78153893518>

7 0
1 year ago
Find the area of the polygon WXYZ with its vertices at W(–3, –2), X(–3, 5), Y(2, 5), and Z(2, –2).
ki77a [65]

Answer:

The area of the polynomial is 35 square unit.

Step-by-step explanation:

It is given that area of the polygon WXYZ with its vertices at W(–3, –2), X(–3, 5), Y(2, 5), and Z(2, –2).

From the below graph it is noticed that the given polynomial is a rectangle with length 5 and width 7.

The distance formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the above formula we get,

WX=7

XY=5

YZ=7

WZ=5

The length of opposing sides are equal.

Using the Pythagoras theorem, the length of diagonal WY and XZ are

WY=\sqrt{(WX)^2+(XY)^2}=\sqrt{7^2+5^2}=\sqrt{74}

XZ=\sqrt{(XY)^2+(YZ)^2}=\sqrt{5^2+7^2}=\sqrt{74}

Since the length of the diagonal are same, therefore the given polygon is a rectangle.

The area of a rectangle is

A=l\times w

Where l is length and w is width.

The area of given polynomial is

A=5\times 7

A=35

Therefore the area of the polynomial is 35 square unit.

6 0
2 years ago
- In the following diagram of triangle QRS, QR = 8 and QS = 17. Determine the value of sin Q. Show how you
dimaraw [331]

Answer:

SinQ=\frac{15}{17}

Step-by-step explanation:

We draw the right triangle as shown in the image attached.

Δ QRS

Where R is the right angle

Given

QR = 8

QS = 17

Now, using Pythagorean Theorem, we can find RS:

QR^2+RS^2=QS^2\\8^2+RS^2=17^2\\RS^2=17^2-8^2\\RS^2=225\\RS=\sqrt{225}\\RS=15

Now, we know the ratio Sine as:

Sin(\theta)=\frac{Opposite}{Hyotenuse}

Where \theta is the angle (here angle Q)

Opposite side is RS (which is 15)

Hypotenuse is given as QS (which is 17)

So,

SinQ=\frac{15}{17}

This is the value of SinQ.

We don't want the angle, so we'll stop here.

5 0
2 years ago
Which represents the reflection of f(x)= square root x over the x-axis?
antiseptic1488 [7]
The reflection of f(x)=sqrt(x) over x-axis will be represented by option a. This is because it is the reflection of the imaginary part of the function f(x)= sqrt(x). Hence the correct answer is a. 

8 0
2 years ago
Read 2 more answers
Find the functions y-intercept algebraically
grigory [225]
To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y. If the equation is written in the slope-intercept form, plug in the slope and the x and y coordinates for a point on the line to solve y. Hope this helped! :)
3 0
2 years ago
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