Determine whether the vectors u and v are parallel, orthogonal, or neither.
2 answers:
The given vectors are and
Two vectors are said to be orthogonal if they are perpendicular to each other. i.e. the dot product of the two vectors is zero.
Let us consider the dot product of the vectors
which is not equal to zero. Hence, the given vectors are not orthogonal.
Two vectors are said to be parallel if one vector is a scalar multiple of the other vector.
Here we can observe that the from the given vectors, one vector can not be expressed as the scalar multiple of the other vector.
Hence, the given vectors are neither parallel nor orthogonal.
Answer:
Neither
Step-by-step explanation:
Given: The given vectors are and
.
To find: To find whether the vectors u and v are parallel, orthogonal, or neither
Solution: Two vectors are said to be orthogonal if they are perpendicular to each other that is the dot product of the two vectors is zero.
Let us consider the dot product of the vectors
which is not equal to zero.
Hence, the given vectors are not orthogonal.
Two vectors are said to be parallel if one vector is a scalar multiple of the other vector.
In the given vectors, it can be observed that , one vector can not be expressed as the scalar multiple of the other vector.
Hence, the given vectors are neither parallel nor orthogonal.
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Answer:
a. Descriptive statistics for the sample.
n= 9
mean X[bar]= 20.36
median Me= 20.30
min: 19.70
max: 21.40
standad deviation S= 0.61
b. 95% Confidence interval [19.88; 20.83]
c. Decision: Support H₀
Step-by-step explanation:
Hello!
I don't have excel so I cannot install PHstat, I've used a statistic software called Infostat for the calculations.
There was a random sample of 9 bottles of shampoo taken to test if the process is operating correctly. If it is, the bottles should weight on average 20 ounces (this would be our study parameter)
The study variable is X: the weight of a bottle of shampoo.
X~N(μ;σ²)
a.
Descriptive statistics for the sample.
n= 9
mean X[bar]= 20.36
median Me= 20.30
min: 19.70
max: 21.40
standad deviation S= 0.61
b. 95% Confidence interval.
Since the variable has a normal distribution and the population variance is unknown, the statistic to use to construct this interval is the Students t:
X[bar] ± * (S/√n)
20.36 ± * (0.61/√9)
[19.88; 20.83]
c. You have to test the hypothesis that the production is operating correctly, if it is so, then:
H₀: μ = 20
H₁: μ ≠ 20
α: 0.05
The statistic value is t= 1.74
p-value: 0.1198
When you use the p-value to decide on a statistical hypothesis, you should always contrast it with the level of significance using the following rule:
If p-value ≤ α, then you reject the null hypothesis.
If p-value > α, then you do not reject the null hypothesis.
Since the p-value is greater than the significance level, you do not reject the null hypothesis. This means that the average weight of the shampoo bottles is 20 ounces, i.e. the process is operating correctly.
I hope it helps!