Answer:

Step-by-step explanation:
The equation of line in the form .
y = mx + c
Where m is the slope and c is the y- intercept .
As given
The lines y=3x-1 and y=ax+2 are perpendicular .
Here 3 is slope for equation of line y=3x-1 and a is slope for equation of line
y=ax+2 .
Now by using properties of the perpendicular lines property .
When two lines are perpendicular than slope of one line is negative reciprocal of the other line .
Thus

Therefore 
Answer:
(See explanation)
Step-by-step explanation:
The function is:

Its simplified form is presented hereafter:

The resultant expression is a linear function, first-order polynomial, whose domain and range are the set of the real numbers.
Answer:
<u>The correct answer is A. 16.5%</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly and to calculate the trend:
2006 2007 Trend
Top Coats 297 223 -24.92%
Parkas 210 210 + 0%
Jackets 213 285 +33.80%
Raincoats 137 259 +89.05
Trench coats 103 127 +23.30%
Total 960 1,104 +15%
2. If the trend shown in these graphs stays constant, what percent of the market will parkas occupy in 2008?
Let's calculate the percent of the market occupied by parkas.
In 2006 = 210/960 = 21.88%
In 2007 = 210/1,104 = 19.02%
In 2008 = 210/1,270 = 16.54% (210 + 0 = 210; 1,104 + 15% = 1,270)
<u>The correct answer is A. 16.5%</u>
-5/2 is the answer. I just took the test and got it right.
Answer:
t = 137.9 years
Step-by-step explanation:
Hi, to answer this question we have to apply an exponential growth function:
A = P (1 + r) t
Where:
p = original population
r = growing rate (decimal form)
t= years
A = population after t years
Replacing with the values given:
A = 6,250 (1 + 3.75/100)^t
A = 6,250 (1 + 0.0375)^t
A = 6,250 (1.0375)^t
1915-1890 = 25 years passed (t)
A = 6,250 (1.0375)^25
A = 15,689
1940-1890 = 50 years passed (t)
A = 6,250 (1.0375)^50
A = 39,381
- When will the population reach 1,000,000?. We have to subtitute A=1000000 and solve for t.
1,000,000= 6,250 (1.0375)^t
1,000,000/ 6,250 =(1.0375)^t
160 = 1.0375^t
log 160 = log 1.0375^t
log 160 = (t ) log 1.0375
log160 / log 1.0375= t
t = 137.9 years