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Ivenika [448]
2 years ago
9

Credit card A offers an introductory APR of 4.1% for the first 3 months and a standard APR of 18.5% thereafter, while credit car

d B offers an introductory APR of 3.7% for the first 3 months and a standard APR of 18.9% thereafter. All else being equal, which of these statements is correct? (Assume all interest is compounded monthly.)
Mathematics
2 answers:
vfiekz [6]2 years ago
6 0
Credit card A
First 3 months:
4.1% / 360 = 0.011% x 30 = 0.34% per month for the first 3 months.
Next 9 months:
18.5% / 360 = 0.051% x 30 = 1.54% per month for the next 9 months.

Credit card B:
First 3 months
3.7% / 360 = 0.010% x 30 = 0.30% per month for the first 3 months
Next 9 months:
18.9% / 360 = 0.0525% x 30 = 1.575% per month for the next 9 months

Credit Card B is the better deal for the first 3 months.
Credit Card A is the better deal for the next 9 months.
dangina [55]2 years ago
3 0

Answer:credit card A for the course of the whole year and credit card B for the first 3 months

Step-by-step explanation:

Just took apex quiz

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Whats 5578 ÷ 68 equal to
kramer

5578/68=82.029411764705882352941176470588

that would be rounded  to 82.02 which is the answer

7 0
2 years ago
Read 2 more answers
Write 9,540,000 in expanded form using exponents to show powers of 10
krek1111 [17]

Answer:

9* 10^{6}+ 5* 10^{5}+4* 10^{4}.

Step-by-step explanation:

Given  :  9,540,000

To find : Write 9,540,000 in expanded form using exponents to show powers of 10.

Solution : We have given 9,540,000

Here 9 is at million place 9000000

5 is at hundred thousand place = 500,000.

4 is at tens thousand place = 40,000

We expanded it as

9, 000,000 + 500,000+40,000.

In term of power of 10.

9* 10^{6}+ 5* 10^{5}+4* 10^{4}.

Therefore,

9* 10^{6}+ 5* 10^{5}+4* 10^{4}.

6 0
2 years ago
If this particular arithmetic sequence, a7=34 and a15=74. What is the value of a21
Ilya [14]
This is an arithmetic sequence, meaning, to get the next term, you simply add some value to the current one, namely the "common difference" "d".

now, we know the 17th term is 34, let's go to the 15term then

34 + d
34 + d + d
34 + d + d + d
34 + d + d + d + d
34 + d + d + d + d + d
34 + d + d + d + d + d + d
34 + d + d + d + d + d + d + d
34 + d + d + d + d + d + d + d + d

now, notice, we got to the 15th term, which is 34  + d + d + d + d + d + d + d + d, or namely 34 + 8d, it just so happen we know is 74, therefore,

\bf 34+8d=74\implies 8d=40\implies d=\cfrac{40}{8}\implies \boxed{d=5}

ok, now that we know what the common difference is, let's find the first term in the sequence using the 7th term of 34,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=7\\
d=5\\
a_7=34
\end{cases}
\\\\\\
a_7=a_1+(7-1)5\implies 34=a_1+(7-1)5
\\\\\\
34=a_1+30\implies \boxed{4=a_1}

and now let's use those 2 found folks, to get the 21st term,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=4\\
d=5\\
n=21
\end{cases}
\\\\\\
a_{21}=4+(21-1)5\implies a_{21}=4+100\implies a_{21}=104
3 0
2 years ago
A grocery store gives away a $10 gift card to every 25th customer and a $20 gift card to every 60th customer. Which customer wil
Novosadov [1.4K]
The 300th customer would be the first to recieve both. They would have given away 5 of the 20$ gift cards and 12 of the 10$ ones for a total of 17 gift cards.
7 0
2 years ago
Camille stopped at the grocery store to buy milk. While at the store, she spotted cans of soup on sale for $2.25 each. If the mi
Mrrafil [7]
$2.25x+$3.50=$35

so, $35-$3.50=$31.50

Then you divide $31.50 by $2.25

That equals 14

So, x=14
8 0
2 years ago
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