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lisabon 2012 [21]
2 years ago
7

Michael has a jar with 24 coins. three eighths of the coins are U.S. coins. The rest of the coins are foreign coins. Michael add

s 12 U.S. coins to the jar. a. What fraction of the coins in the jar are foreign coins now? Show your work or explain how you know. Michael continues to add U.S. coins to the jar. b. How many more U.S. coins must Michael add to the jar so that one eighth of the coins are foreign coins? Show your work or explain how you know.
Mathematics
1 answer:
Lera25 [3.4K]2 years ago
7 0
Explanation: 24/8=3 3x3=9 9 coins are U.S coins 24-9=15 15 coins are foreign
15 coins= five eights so 3 coins are one eight if he adds twelve it’s going to be
4x3=12 so it’s seven eights.
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Answer: 43 more times

2580÷60=43.

Step-by-step explanation: 43×60 =2580

This proves that 43 times is correct.

6 0
2 years ago
The train station clock runs too fast and gains 7 minutes every 4 days. How many minutes and seconds will it have gained at the
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4 days 10 days Cross Multiplication
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7 mins x

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2 years ago
The number of bacteria in a culture is given by the function n(t) =950e^0.45t Where t is measured in hours A) what is the contin
tatiyna

Answer:

a) The continuous rate of growth of this bacterium population is 45%

b) Initial population of culture at t = 0 is 950 bacteria

c) number of bacterial culture contain at t = 5 is 9013 bacteria

Step-by-step explanation:

The number of bacteria in a culture is given by

n(t) = 950e^{0.45t}

a) rate of growth is

Bacteria growth model N(t) = noe^{rt}

Where r is the growth rate

hence r = 0.45

              = 45%

b) Initial population of culture at t = 0

n(0) = 950e^{0.45(0)}

       = 950e^{0}

       = 950 bacteria

c) number of bacterial culture contain at t = 5

n(5) =  950e^{0.45(5)}

      = 950e^{2.25}

      = 9013.35

      = 9013 bacteria

6 0
2 years ago
The rectangle below has an area of 6n^4+20n^3+14n^26n 4 +20n 3 +14n 2 6, n, start superscript, 4, end superscript, plus, 20, n,
Sindrei [870]

Given:

Area of rectangle = 6n^4+20n^3+14n^2

Width of the rectangle is equal to the greatest common monomial factor of 6n^4, 20n^3,14n^2.

To find:

Length and width of the rectangle.

Solution:

Width of the rectangle is equal to the greatest common monomial factor of 6n^4, 20n^3,14n^2 is

6n^4=2\times 3\times n\times n\times n\times n

20n^3=2\times 2\times 5\times n\times n\times n

14n^2=2\times 7\times n\times n

Now,

GCF(6n^4, 20n^3,14n^2)=2\times n\times n=2n^2

So, width of the rectangle is 2n^2.

Area of rectangle is

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Taking out GCF, we get

Area=2n^2(3n^2+10n+7)

We know that, area of a rectangle is the product of its length and width.

Since, width of the rectangle is 2n^2, therefore length of the rectangle is (3n^2+10n+7).

5 0
2 years ago
Round 4,398,202 to the nearest 100
Klio2033 [76]
In the hundreds spot is a 2 and 2 is under 5 so we round down which would be 4 398 200
5 0
2 years ago
Read 2 more answers
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