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SVEN [57.7K]
1 year ago
12

1. Yejin plans to retire at age 60. She wants to create an annuity fund, which will pay her a monthly allowance of $4000 during

her retirement. She wants to save enough money so that the payments lasts for 30 years. A financial advisor has told her the she can expect to earn 5% interest on her funds, compounded annually.
2. Yejin has just turned 28 years old. She currently has no retirement savings. She wants to save part of her salary each month into her annuity fund. Calculate the amount Yejin needs to save each month, to meet her retirement goal.
Mathematics
1 answer:
dolphi86 [110]1 year ago
3 0

9514 1404 393

Answer:

  $3891.10

Step-by-step explanation:

This question is a bit unusual in that the interest is compounded annually, but payments and withdrawals are made monthly. The effective monthly rate is ...

  1.05^(1/12) -1 = 0.407412378% = i

We assume that payments to the annuity are made at the end of the month, and that withdrawals are made at the beginning of the month. (The last payment and the first withdrawal are made on the same day.)

The amount of money required in the fund is ...

  A = $4000(1 -(1.00407^-360))/(1 -1.00407^-1) = $757,712.88

The amount of money needed each month to be put into the fund is P, where ...

  $757,712.88 = P(1 -1.00407)^(-12(60-28))/(1 -1.00407^-1) = 194.7297P

  P = $757,712.88/194.7297 = $3891.10

Yejin needs to save $3891.10 each month to meet her retirement goal.

_____

<em>Sanity check</em>

Yejin wants payments for 30 years from the fund to which she has contributed for 32 years. The similarity of the time periods means that Yejin's monthly contribution will need to be very similar to the amount she plans to withdraw.

The only ways to reduce the required contribution are to earn a higher interest on deposits, or to adjust the relative time periods (retire later).

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First of all, a bit of theory: since the area of a square is given by

A = s^2

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s = \sqrt{A}.

Moreover, the diagonal of a square cuts the square in two isosceles right triangles, whose legs are the sides, so the diagonal is the hypothenuse and it can be found by

d = \sqrt{s^2+s^2} = \sqrt{2s^2} = s\sqrt{2}

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With that being said, your function could be something like this:

double diagonalFromArea(double area) {

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2 years ago
Joanna pays $40 plus a $2 surcharge each month for her high-speed Internet service. Which table BEST represents the relationship
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2 years ago
Chandra created a budget matrix based on her regular and expected expenses for the year. Expense Jan. Feb. Mar. Apr. May June Ju
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Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

Therefore, you start by adding up each month total expenses, which are ;

January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

≅ $244

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Answer:

Step-by-step explanation:

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2 years ago
Assemble the proof by dragging tiles to the statements and reasons columns
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Here, I did the assignment. I wish you good luck!

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