Answer:
<h2>{5}</h2>
Step-by-step explanation:

Answer:
It will take 2.6 hours by Daniel to catch up with Frank.
Step-by-step explanation:
Let Daniel will catch up with Frank after t hours.
Now, Frank will go 13 miles in
hours.
So, the distance traveled by Frank in (t + 0.228) hours with 45 mph speed will be equal to the distance traveled by Daniel in t hours with 50 mph speed.
Hence, 45(t + 0.288) = 50t
⇒ 5t = 13
⇒ t = 2.6 hours.
Therefore, it will take 2.6 hours by Daniel to catch up with Frank. (Answer)
We have to choose the correct answer for the center of the circumscribed circle of a triangle. The center of the circumscribed circle of a triangle is where the perpendicular bisectors of a triangle intersects. In this case P1P2 and Q1Q2 are perpendicular bisectors of sides AB and BC, respectively and they intersect at point P. S is the point where the angle bisectors intersect ( it is the center of the inscribed circle ). Answer: <span>P.</span>
<h3>
Answer:</h3>
- f(x) = -2x^3 +3x^2 +11x -6
- see attached
- an infinite number. Since the magnitude of the leading coefficient is not specified, it may be any negative number. (We have chosen the smallest magnitude integer that makes all coefficients be integers.)
<h3>
Step-by-step explanation:</h3>
1. When "a" is a root of a polynomial, (x -a) is a factor of it. For the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).
In order to make the leading coefficient be negative, we need to multiply this product by a negative number. Any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.
Then ...
... f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)
... = -(2x² +3x -2)(x -3)
... = -(2x³ -3x² -11x +6)
... f(x) = -2x³ +3x² +11x -6
2. A graph created by the Desmos on-line graphing calculator is shown, and the zeros are highlighted.
3. As indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. You want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.
Answer:
The events a) and c) are mutually exclusive.
Step-by-step explanation:
a) This is mutually exclusive, each card has a unique value between 2 and 10, or it is a jack, queen, king, or an Ace. A single card cant have two different values at the same time.
b) This is not mutually exclusive, since you can get a king of clubs. Each card can have any combination of one suit and one value.
c) A face card is either a Jack, a Queen or a King, it is not an Ace. For the same argument of a), a card cant have two different values, therefore this event is mutually exclusive.
d) This is not mutually exclusive, since a card can have any suit independently of the value it has (same argument than b), therefore, a card can be a face card and a spade at the exact time.
Therefore, events a and c are mutually exclusive.