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Irina-Kira [14]
2 years ago
6

A researcher is comparing random samples of white, black, and Hispanic Americans for differences in income, family size, and yea

rs of education. Which of the following tests of significance would be useful for all three dependent variables?
a. t test for small samples
b. t test for difference in means
c. anova
d. the test for the significance of the difference between sample proportions
Mathematics
1 answer:
kumpel [21]2 years ago
7 0

Answer: c) annova

Step-by-step explanation:

This is because ANNOVA is a test of differences between 3 groups.

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y=-10x

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y=-10x

y/x=-10

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B) Find the principal that yields an interest of Rs 2240 at the rate of 10% p.a. in 3
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The dot plots show the number of first cousins the boys and girls in Miss Campbell‘s class have. Based on the dot plot, which se
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its the threed one.

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2 years ago
A math teacher tells her students that eating a healthy breakfast on a test day will help their brain function and perform well
kogti [31]

Answer:

Step-by-step explanation:

Hello!

To test the claim that eating a healthy breakfast improves the performance of students on their test a math teacher randomly asked 46 students what did they have for breakfast before they took the final exam and classified them as:

<u>Group 1</u>: Ate healthy breakfast

X₁: Number of students that ate a healthy breakfast before the exam and earned 80% or higher.

n₁= 26

<u>Group 2: </u>Did not eat healthy breakfast

X₂: Number of students that did not eat a healthy breakfast before the exam and earned 80% or higher.

n₂= 20

After the test she counted the number of students that got 80% or more in the test for each group obtaining the following sample proportions:

p'₁= 0.50

p'₂= 0.40

The parameters of study are the population proportions, if the claim is true then p₁ > p₂

And you can determine the hypotheses as

H₀: p₁ ≤ p₂

H₁: p₁ > p₂

α: 0.05

Z= \frac{(p'_1-p'_2)-(p_1-p_2)}{\sqrt{p'(1-p')[\frac{1}{n_1} +\frac{1}{n_2}] } } }≈N(0;1)

pooled sample proportion: p'= \frac{x_1+x_2}{n_1+n_2} =\frac{13+8}{46} = 0.46

Z_{H_0}= \frac{(0.5-0.4)-0}{\sqrt{0.46(1-0.46)[\frac{1}{26} +\frac{1}{20}] } } }= 0.67

p-value: 0.2514

The decision rule is:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The p-value: 0.2514 is greater than the significance level 0.05, the test is not significant.

At a 5% significance level you can conclude that the population proportion of math students that obtained at least 80% in the test and had a healthy breakfast is equal or less than the population proportion of math students that obtained at least 80% in the test and didn't have a healthy breakfast.

So having a healthy breakfast doesn't seem to improve the grades of students.

I hope this helps!

5 0
2 years ago
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lesantik [10]
Substract 3 from the total and divide it with 2
one of them is 5 and the other one is 8.
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