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lina2011 [118]
2 years ago
14

The density of a fish tank is 0.4fish over feet cubed. There are 12 fish in the tank. What is the volume of the tank?

Mathematics
2 answers:
ICE Princess25 [194]2 years ago
7 0
Answers?? need a little bit of a hint of them please.
Mnenie [13.5K]2 years ago
3 0

Answer:

30ft

Step-by-step explanation:

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If 153=2(z+z)n153=2(z+z)n153, equals, 2, left parenthesis, z, plus, z, right parenthesis, n, then what is the value of 2n(2z)-19
Nostrana [21]
What you must do for this case is to rewrite the first expression to find its value.
 We have then:
 153 = 2 (z + z) n
 Rewriting:
 153 = 2n2z
 Then,
 2n (2z) -193
 Substituting
 153-193 = -40
 Answer:
 the value of 2n (2z) -193 is
 -40
8 0
2 years ago
Sean has 15,000 to invest she will put some of it into a fund that pays 4.5% annual interest in the rest in a certificate of dep
DENIUS [597]

Answer:$12500 was invested into the account that pays 4.5% annual interest..

$2500 was invested into the the certificate of deposit that pays 1.8% annual interest..

Step-by-step explanation:

Let x represent the amount invested into the account that pays 4.5% annual interest.

Let y represent the amount invested into the certificate of deposit that pays 1.8% annual interest.

Sean has 15,000 to invest. She will put some of it into a fund that pays 4.5% annual interest and the rest in a certificate of deposit that pays 1.8% annual interest. This means that

x = y + 15000

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

Considering the account earning 4.5% interest, the interest would be

I = (x × 4.5 × 1)/100 = 0.045x

Considering the account earning 11% interest, the interest would be

I = (x × 1.8 × 1)/100 = 0.018y

if she wants to earn 4.05% annual interest on the total amount, the amount would be

4.05/100 × 15000 = 607.5

Therefore,

0.045x + 0.018y = 607.5 - - - - - - - - - - -1

Substituting x = 15000 - y into equation 1, it becomes

0.045(15000 - y) + 0.018y = 607.5

675 - 0.045y + 0.018y = 607.5

- 0.045y + 0.018y = 607.5 - 675

- 0.027y = - 67.5

y = - 67.5/- 0.027

y = $2500

x = 15000 - y = 15000 - 2500

x = $12500

6 0
2 years ago
A jet flies 425 km from Ottawa to Québec at rate v + 60. On the return flight, the
Marina CMI [18]

Answer:

a. \frac{- 42,500}{(v + 60)(v - 40)}

Step-by-step Explanation:

Given:

Distance Ottawa to Québec = 425 km

Initial flight rate = v + 60

Return flight rate = v - 40

t = \frac{d}{r}

Required:

Flight times difference of the initial and return flights

Solution:

=>Flight time of the initial flight:

t = \frac{d}{r}

t = \frac{425}{v + 60}

=>Flight time of the return flight:

t = \frac{425}{v - 40}

=>Difference in flight times:

\frac{425}{v + 60} - \frac{425}{v - 40}

\frac{425(v - 40) -425(v + 60)}{(v + 60)(v - 40)}

\frac{425(v) - 425(40) -425(v) -425(+60)}{(v + 60)(v - 40)}

\frac{425v - 17000 -425v - 25500}{(v + 60)(v - 40)}

\frac{425v - 425v - 17000 - 25500}{(v + 60)(v - 40)}

\frac{- 42,500}{(v + 60)(v - 40)}

3 0
2 years ago
Which is the additive inverse of the complex number -8+3i?
lawyer [7]
The additive inverse of a complex z is a complex number -z, so that

\mathsf{z+(-z)=-z+z=0+0i=0}


Finding -z:

\mathsf{z=-8+3i}\\\\\\ \mathsf{z+(-z)=0+0i}\\\\\ \mathsf{-8+3i+(-z)=0+0i}\\\\ \mathsf{-z=0+0i+8-3i}\\\\ \mathsf{-z=(0+8)+(0i-3i)}\\\\ \boxed{\begin{array}{c}\mathsf{-z=8-3i} \end{array}}\qquad\checkmark


If you're having problems understanding this answer, try seeing it through your browser: <span>brainly.com/question/2159647


</span>I hope this helps.


Tags: <em>complex number additive inverse opposite algebra</em>

3 0
2 years ago
Which table shows a function that is decreasing only over the interval (–1, ∞)? A 2-column table with 6 rows. The first column i
Lemur [1.5K]

Answer:

B. f(x) ≤ 0 over the interval [0, 2]. D.f(x) > 0 over the interval (–2, 0). E.f(x) ≥ 0 over the interval [2, ).

Step-by-step explanation:

Those are the 3 answers. Just did it on edge.

8 0
2 years ago
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