Answer:
Part a) 
Part b) The coordinates of the point are 
Step-by-step explanation:
Part a) Find the equation representing the ladder
we have the ordered pairs
(0,4) and (2,0)
Find the slope
Find the equation of the line in slope intercept form
we have
substitute
Part b) A square box just fits under the ladder.Find the coordinates of the point where the box touches the ladder.
If the box is a square
the x-coordinate of the point where the box touches the ladder must be equal to the y-coordinate
x=y
substitute
therefore
The coordinates of the point are
Answer:
Range = [- 2.5, 0.5] = [ - 5/2, 1/2]
Step-by-step explanation:
Smallest value of cos α = - 1,
largest value of cos α = 1.
When cos 4x = - 1, y=3/2cos4x-1 = 3/2*(-1) - 1 = - 5/2 = - 2 1/2 = - 2.5
When cos 4x = 1, y=3/2cos4x-1 = 3/2*1 - 1 = 1/2 = 0.5
Range = [- 2.5, 0.5] = [ - 5/2, 1/2]
Answer:
$42.88
Step-by-step explanation:
Let's create a proportion using the following setup:
cost/pounds=cost/pounds
We know that it costs $20.42 for a 10 pound turkey.
$20.42/10 pounds= cost/pounds
We don't know how much a 21 pound turkey costs, so we can say that it costs $x for a 21 pound turkey.
$20.42/ 10 pounds= $x/ 21 pounds
20.42/10=x/21
We want to find x, by getting x by itself.
x is being divided by 21. The inverse of division is multiplication. Multiply both sides by 21.
21*(20.42/10)=(x/21)*21
21* 20.42/10=x
21*2.042=x
42.882=x
Round to the nearest cent, or hundredth.
42.88=x
x= $42.88
A 21 pound turkey costs $42.88
we know that
The domain of the function are the values of x for which the function exists and the range of the function are the values of the function
in this problem
The domain of the function are the values 
The range of the function are the values 
therefore
<u>the answer is the option B</u>
Answer:
Answer is given below under explanation
Step-by-step explanation:
We are told that the domain is a set of real numbers. Let's depict by a & b.
We will use the following symbols;
∀ means for all
Ǝ there exists
∧ means logical conjuction
Thus;
A) Ǝ a,b : ( a/b < 1, b/a < 1 )
B) ∀ a : ( a > 0 = 1/a > 0 )
C) Ǝ a,b : (a + b = ab)
D) ∀ a,b : [ ( a > 0 ) ∧ ( b > 0 ) = (( a/b > 0 ) ∧ ( b/a > 0 ))]
E) ∀ b : [( b > 0 ) ∧ ( b < 1) = ( 1/b > 1 )]
F) n ( ( Ǝ x ∀ b ( a < b ) )
