A grapefruit is 8% heavier than an orange, and an apple is 10% lighter than theorange.By what percentage is the grapefruit heavi
er than the apple?
2 answers:
<h2>Answer:</h2>
Hence, the grapefruit is 20% heavier than the apple.
<h2>Step-by-step explanation:</h2>Let the weight of orange be x.
This means that the weight of grapefruit is:
1.08x
( Since grapefruit is: 8% heavier than orange )
Also, the weight of apple is 10% lighter than apple.
This means that the weight of apple is: 0.90 x
Hence, the percent change in the weight of grapefruit as compared to apple is calculated by:
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<u>Given:</u>
The given equation is
We need to determine the extraneous solution of the equation.
<u>Solving the equation:</u>
To determine the extraneous solution, we shall first solve the given equation.
Applying the log rule , we get;
Again applying the log rule, if then
Thus, we have;
Simplifying the equation, we get;
Factoring the equation, we get;
Thus, the solutions are
<u>Extraneous solutions:</u>
The extraneous solutions are the solutions that does not work in the original equation.
Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.
Thus, we get;
Since, we know that is undefined.
Thus, we get;
Undefined = Undefined
This is false.
Thus, the solution x = 3 does not work in the original equation.
Hence, x = 3 is an extraneous solution.
Similarly, substituting x = -7, in the original equation. Thus, we get;
Simplifying, we get;
Undefined =
Undefined = 3.06
This is false.
Thus, the solution x = -7 does not work in the original solution.
Hence, x = -7 is an extraneous solution.
Therefore, the extraneous solutions are x = 3 and x = -7
Answer:
See the explanation
Step-by-step explanation:
(a)
H0: Consultant with more experience has the higher population mean service rating.
H1: Consultant with more experience doesn't have the higher population mean service rating.
(b)
t = 1.9923 (see the attached image)
(c)
The degrees of freedom for the test statistic,
df = 16
The P-value of the one tailed t- test with 16 degrees of freedom is,
P−value = tdist(X,df,tails)
P-value = tdist(1.9923,16,1)
P-value = 0.032
(d)
Since, P-value 0.032 is less than the significance level 0.05, there is an enough evidence to reject the null hypothesis.
Hence, there is a sufficient evidence to conclude that Consultant with more experience doesn't have the higher population mean service rating.
Hope this helps!
