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Nimfa-mama [501]
2 years ago
12

The exponential functions y=(1-25)^x-2/5. -10 is shown hraphed along woth the horizontal line y=115 their intersection is (a,115

) start by using wht they give you for the point of intersection ans substitute that into the given equation
Mathematics
1 answer:
evablogger [386]2 years ago
3 0

Answer:26

Step-by-step explanation:

Y=1.25^x-2/5-10

Take log of both sides

So Y+10=1.25^x-2/5

So log to base 10 of the two sides of the equation is

Log(Y+10)=X-2/5log1.25.

To make X the subject, divide both sides by log1.25.

Log(Y+10)/log1.25=X-2/5.

Recall that Y was given to be 115

It becomes log(115 +10)/Log1.25=x-0.4

21.64=x-0.4

X=25.6

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1/4 of the roses are red, 1/3 of the remainder are yellow and the rest are pink. There are 24 more pink roses than red roses. Ho
Alika [10]
<h3>There are 96 roses altogether</h3>

<em><u>Solution:</u></em>

Let "x" be the number of roses

From given,

<em><u>1/4 of the roses are red</u></em>

Red\ roses = \frac{1}{4} \times x\\\\Red\ roses = \frac{x}{4}

<em><u>1/3 of the remainder are yellow</u></em>

Remaining = x - \frac{x}{4}\\\\Remaining = \frac{3x}{4}

Therefore,

Yellow\ roses = \frac{1}{3} \times \frac{3x}{4}\\\\Yellow\ roses = \frac{x}{4}

<em><u>Rest are pink</u></em>

Remaining = \frac{3x}{4} - \frac{x}{4}\\\\Remaining = \frac{2x}{4}\\\\Remaining = \frac{x}{2}

Therefore,

Pink\ Roses = \frac{x}{2}

There are 24 more pink roses than red roses

Therefore,

Number of pink roses = 24 + red roses

\frac{x}{2} = 24 + \frac{x}{4}\\\\\frac{x}{2} -  \frac{x}{4} = 24\\\\\frac{x}{4} = 24\\\\x = 24 \times 4\\\\x = 96

Thus there are 96 roses altogether

7 0
2 years ago
The number of gallons of gas that were in the tank minus 9 leaves 3 gallons
erastovalidia [21]
<h3>Hey!</h3>

<em><u>To solve the missing number of the original amount of gallons that were in the tank is simply by adding the two numbers we have: </u></em>

<em><u></u></em>

9+3= 12 gallons

<u><em>To make sure 12 was the original number, subtract 12 from 9. </em></u>

<u><em /></u>

<u><em>12-9= 3 gallons </em></u>

So your answer to your question is 12 gallons!

Hope this helped! °ω°

7 0
2 years ago
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Mr. Richard's science class is conducting a variety of experiments with projectiles and falling objects. Two groups of students
UNO [17]

Answer:

1.  Group C; 2.  Group B; 3.  Group D; 4.  Group A

Step-by-step explanation:

These equations are in the form

y=-4.9t^2+v_0t+h_0\\\text{or}\\y=-16t^2+v_0t+h_0, where v₀ is the initial velocity and h₀ is the initial height.

The first equation has no value for v₀ and a value of 19 for h₀.  This means there is no velocity, so the ball is dropped, and since the initial height is 19, it is dropped from 19 meters.  This makes it group C.

The second equation has a value of 50 for v₀ and no value for h₀.  This means the initial velocity is 50 and there is no initial height.  This makes it group B.

The third equation has no value for v₀ and a value of 50 for h₀.  This means there is no initial velocity, so the ball is being dropped, and the initial height is 50.  This makes it group D.

The fourth equation has a value of 19 for v₀ and no value for h₀.  This means the initial velocity is 19 and there is no initial height.  This makes it group A.

7 0
2 years ago
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Use a table of numerical values of f(x,y) for (x,y) near the origin to make a conjecture about the value of the limit of f(x,y)
grigory [225]
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Consider an arbitrary line through the origin y=mx, so that we rewrite the above as

\displaystyle\lim_{x\to0}\frac{mx^2}{x^2+2m^2x^2}=\lim_{x\to0}\frac m{1+2m^2}=\frac m{1+2m^2}

The value of the limit then depends on the slope m of the line chosen, which means the limit is path-dependent and thus does not exist.
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A person drives 15km to the shops at an average speed of 30km/h, then drives back at an average speed of 60km/h. What is their a
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30 km/h to the store. 60 km/h back from the store.

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90 \ 2

Final answer: 45
8 0
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