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Nimfa-mama [501]
2 years ago
12

The exponential functions y=(1-25)^x-2/5. -10 is shown hraphed along woth the horizontal line y=115 their intersection is (a,115

) start by using wht they give you for the point of intersection ans substitute that into the given equation
Mathematics
1 answer:
evablogger [386]2 years ago
3 0

Answer:26

Step-by-step explanation:

Y=1.25^x-2/5-10

Take log of both sides

So Y+10=1.25^x-2/5

So log to base 10 of the two sides of the equation is

Log(Y+10)=X-2/5log1.25.

To make X the subject, divide both sides by log1.25.

Log(Y+10)/log1.25=X-2/5.

Recall that Y was given to be 115

It becomes log(115 +10)/Log1.25=x-0.4

21.64=x-0.4

X=25.6

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Read 2 more answers
point M with coordinates (3,4) is the midpoint of the line AB and A has the point (-1,6). what is the point of B?
irina [24]

Answer:

  B = (7, 2)

Step-by-step explanation:

B = 2M -A

B = 2(3, 4) -(-1, 6) = (2·3-(-1), 2·4-6)

B = (7, 2)

_____

The expression for the other end point, B, comes from the equation for the midpoint.

  M = (A +B)/2

  2M = A + B . . . . . multiply by 2

  2M -A = B . . . . . . subtract A to get an expression for B

4 0
1 year ago
martin will roll a number of cube 150 times.The number cube is labeled 1 to 6.How many times could Martin expect to roll a numbe
olga_2 [115]
So the probability of rolling a number greater than 2 is 4/6. So 4/6 times 150 should give you the answer 100.
7 0
2 years ago
A study of 25 graduates of four-year public colleges revealed the mean amount owed by a student in student loans was $55,051. Th
Kitty [74]

Answer:

a

   The  90%  confidence interval is  52561.13  <  \mu  < 57540.8

b

Confidence interval for the population men between <u>$52561.13</u>  up to <u>$57540.8</u>

Step-by-step explanation:

From the question we are told that

   The sample size is  n = 25

     The  sample mean is  \= x  =  \$ 55,051

     The standard deviation is  \sigma  =  \$ 7,568

Given that the confidence level is  90% then the level of confidence is mathematically represented as

             \alpha  =  100 -90

              \alpha  = 10\%

             \alpha  = 0.10

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table the values is  

               Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically  represented as

               E =  Z_{\frac{ \alpha }{2} } * \frac{ \sigma }{\sqrt{n} }

substituting values

               E =  1.645 * \frac{ 7568}{ \sqrt{ 25} }

             E =  2489.9

The 90% confidence interval is mathematically evaluated as

       \= x  -E  <  \mu  <  \= x  +E

substituting values

     55051  - 2489.8  <  \mu  <  55051  + 2489.8

     52561.13  <  \mu  < 57540.8

6 0
2 years ago
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