Answer:
Option D.
Step-by-step explanation:
In the given graph x-axis represents the number of owners and y-axis represents yearly cost of pets, in hundreds.
It is given that the graph passes through the points (1,15), (3,7) and (10,0).
We need to check whether (4.5, 6) is a realistic solution for the function or not. (4.5,6) point represents
Number of owners = 4.5
yearly cost of pets = 6
It is realistic that owners spend $600 a year on their pet(s).
Number of owners can not be a fraction value. So, it is not realistic to have 4.5 owners.
Therefore, the correct option is D.
 
        
                    
             
        
        
        
Answer:
Jamie should have reversed the inequality when using the division property of inequality.
Step-by-step explanation:
Jamie wrote
500 − 30x ≥ 200
Subtract 500 from both sides
500-500-30x ≥ 200-500
-30x ≥ -300
Divide both sides by -30
x ≥ 10
Instead of reversing the inequality when using the division property of inequality
500 − 30x ≥ 200
Subtract 500 from both sides
500-500-30x ≥ 200-500
-30x ≥ -300
Divide both sides by -30
x <or= 10
 
        
                    
             
        
        
        
Answer:
FA = 25.87  
Step-by-step explanation:
Given: BD = 30 , DF = 5 , EF = 16 
To find: FA
Rectangular box is a Cuboid.
Figure attached.
AB = FE = 16
So,
In  ΔADB
using Pythagoras theorem,

Again using Pythagoras theorem in Δ ADF we get

Therefore, FA = 25.87
 
        
                    
             
        
        
        
Answer:
The answer to the question is
The ratio of the two gas pressures    , that is Px to Py = 1/6
 , that is Px to Py = 1/6
Step-by-step explanation:
Let the gases Volumes be V₁ and V₂
Where volume of X = V₁ and
volume of Y = V₂
The volume of Y is half the volume of X
∴ V₂  =   × V₁
 × V₁
Let the number of moles be n₁ and n₂ in X and Y respectively
therefore  n₂ = 3 × n₁ 
The pressure of the gas in X is Pₓ and the pressure of the gas in Y is   then we have
 then we have
P₁ × V₁  = n₁ × R × T₁ , and P₂ × V₂ = n₂ × R × T₂
(P₁ × V₁)/(n₁ × T₁) = (P₂ × V₂)/(n₂ × T₂)
but T₁ = T₂
Therefore
(P₁ × V₁)/n₁ = (P₂ × V₂)/n₂.  However  n₂ = 3 × n₁  and V₂  =   × V₁ therefore substituting in the equation we have
 × V₁ therefore substituting in the equation we have
(P₁ × V₁)/n₁ = (P₂ ×   × V₁ )/(3 × n₁) from where
 × V₁ )/(3 × n₁) from where
P₁ /P₂ =  ( × V₁ × n₁)/(V₁×3 × n₁) =0.5/3 = 1/6
 × V₁ × n₁)/(V₁×3 × n₁) =0.5/3 = 1/6
The ratio of  = 1/6
 = 1/6