Part A: [<span>P + (A + G) - M
</span>Part B: [0.75 + (0.25 + 0.30) - 0.20] = 1.1
Answer
Find out the m∠p .
To prove
As in ΔDAB is a right triangle
Apply pythagorean theorem
Hypotenuse ² = Perpendicular ² + Base²
DB² = AB² + AD²
AB = 5 units
AD = 6 units
Put in the above formula
DB² = 5² + 6²
= 25 + 36
= 61

= 7.8 units (approx)
Now in ΔDCB is a right triangle .
By using the trignometric identity .


As DC = 4 units
DB = 7.8 units (approx)
Put all the values in the trignometric identity .


∠p = 59.15 ° (approx)
Correction:
Because F is not present in the statement, instead of working onP(E)P(F) = P(E∩F), I worked on
P(E∩E') = P(E)P(E').
Answer:
The case is not always true.
Step-by-step explanation:
Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.
And for any two mutually exclusive events, E and E',
P(E∩E') = 0
Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then
P(E)P(E') cannot be equal to zero.
So
P(E)P(E') ≠ 0
This makes P(E∩E') different from P(E)P(E')
Therefore,
P(E∩E') ≠ P(E)P(E') in this case.
The answer to the question is a
Lets find all the numbers..
x (1st number)
x + 2 ( 2nd number)
x + 4 (3rd number)
x + 6 (4th number)
x + 8 (5th number)
x + 10 (6th number)
Now add all those expressions and set them equal to 270 because that is the total.
x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 270
6x + 30 = 270
6x = 240
x = 40
Now we will substitute 40 for x in the expression of the second number.
x + 2
40 + 2
42
So the second number is 42
Hope this helps :)