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Brilliant_brown [7]
2 years ago
9

Sam is playing the video game Moon Attack. The purpose of the game is to shoot aliens that are

Mathematics
1 answer:
earnstyle [38]2 years ago
7 0

Answer:

60 pi/3

Step-by-step explanation:

I took the test

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Derek has 12 shirt in his closet. If 2 out of every 3 of these shirts are striped,how many striped shirts does Derek have in his
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12 divided by 3 is 4
if 2 of each of these is stripped that means 8/12 are striped
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Which statement is true about this data set?
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The data set has no outliers
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The owners of Prim's Pizza are concerned that many of their customers are starting to purchase pizza from The Pizza Palace becau
AleksandrR [38]

Answer:

(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953

(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047

And the confidence interval for the difference is between:

27.953 \leq \mu_1 -\mu_2 \leq 32.047

Step-by-step explanation:

We have the following info given:

\bar X_1 = 240 sample mean for medium Pizzas from Prim's

\bar X_2 = 210 sample mean for medium Pizzas from Pizza Place

s_1 =8.6 sample deviation for Prim's

s_2 =5.7 sample deviation for Pizza Palca

n_1 =n_2 = 100  sample size selected for each case

The confidence interval for the difference of means is given by:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

And for the 95% confidence we need a significance level of \alpha=1-0.95=0.05 and \alpha/2 =0.025, the degrees of freedom are given by:

df= n_1 +n_2 -2= 100+100-2 =98

And the critical value would be

t_{\alpha/2}= 1.984

And replacing we got:

(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953

(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047

And the confidence interval for the difference is between:

27.953 \leq \mu_1 -\mu_2 \leq 32.047

8 0
2 years ago
Aisha bought 15 apples and oranges for $9.00. Each orange costs $0.50, and each apple costs $0.65. Let x represent the number of
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I might be wrong but i think its 
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A large city in the ancient world was square-shaped. measured in miles, its area numerically exceeded its perimeter by about 132
melisa1 [442]
Area = perimeter + 132.  

Let  each side of the city be x miles long, then:-

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13.7 * 13.7   to nearest 10th
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