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1 year ago

A particle travels 24.6 km in 30 minutes. Find the

Mathematics

1 answer:

tatyana61 [14]1 year ago

8 0

Answer:

See the solutions below

Step-by-step explanation:

Given data

Distance = 24.6km

in meters= 24.6*1000= 24600m

time= 30 minutes

in seconds= 30*60= 1800

int hours= 0.5 hour

speed of the particle in

(i) km/h= 24.6/0.5= 49.2 km/h

(ii) m/s.= 24600/ 1800= 13.66 m/s

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A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result:

$\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}$ .

Therefore:

$\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}$ .

Lookup $0.1985$ on a normal distribution table. The corresponding $z$ -score is $0.52$ . (In other words, $P(0 \le Z \le 0.52) = 0.1985$ .)

Given that

$z = 0.52$ ,
$x =5$ , and
$\sigma = 2$ ,

Solve the equation $\displaystyle z = \frac{x - \mu}{\sigma}$ for the mean, $\mu$ :

$\displaystyle 0.52 = \frac{5 - \mu}{2}$ .

$\mu = 5 - 2 \times 0.52 = 3.96$ .

3 0

2 years ago

I have k quarters, five less quarters than nickels and one more than twice as many dimes as quarters. Find the value of the coin

Alenkinab [10]

Answer:

(35k + 20) cents

Step-by-step explanation:

First of all, let us have the value of each unit:

1 quarter = 25 cents

1 nickel = 5 cents

1 dime = 10 cents

Given that number of quarter = k

Quarters are 5 lesser than Nickels, so number of nickels = k+5

One more than twice as many dimes as quarters:

k = 2 $\times$ Number of Dimes + 1

So, number of dimes = $\frac{1}{2}(k-1)$

Value of quarters = $25 \times k$ cents

Value of nickels = $5 \times (k+5) = (5k+25)\ cents$

Value of dimes = $\frac{1}{2}(k-1) \times 10 = (5k-5)\ cents$

So, total value of coins =

$25k + 5k +25 +5k-5\\\Rightarrow (35k+20)\ cents$

5 0

2 years ago

Read 2 more answers

ben needs to convert 500 US dollars to the japanese yen. one american dollar is worth 123.3 yen. how many yen will he have

laiz [17]

Answer:

<u>The correct answer is 61,650 Yens</u>

Step-by-step explanation:

US$ in cash that Ben has = 500

Exchange rate (US$/Yen) = 1 : 123.3

For calculating the total amount in Yens that Ben has, we use this formula:

Yens in Cash = US$ in Cash * Exchange rate given

Yens in Cash = 500 * 123.3

Yens in Cash = 61,650

<u>After converting the US$ 500 Ben has, he will receive Yens 61,650</u>

6 0

2 years ago

Which equation represents the line that passes through (–6, 7) and (–3, 6)? y = –y equals negative StartFraction one-third EndFr

DiKsa [7]

Answer:

$y=-\frac{1}{3} x+5$

Step-by-step explanation:

Notice that the answers they give you to choose from are all lines in slope y-intercept form, it would be very simple to just find the answer finding yourself the slope and y-intercept of the line in question.

Since they give you two points $(x_1,y_1)$ and $(x_2,y_2)$ for the line, use them to find the slope of the line that goes through them, with the formula: $slope=\frac{y_2-y_1}{x_2-x_1} =\frac{7-6}{-6-(-3)} =\frac{1}{-3} =-\frac{1}{3}$