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1 year ago

A particle travels 24.6 km in 30 minutes. Find the

Mathematics

1 answer:

tatyana61 [14]1 year ago

8 0

Answer:

See the solutions below

Step-by-step explanation:

Given data

Distance = 24.6km

in meters= 24.6*1000= 24600m

time= 30 minutes

in seconds= 30*60= 1800

int hours= 0.5 hour

speed of the particle in

(i) km/h= 24.6/0.5= 49.2 km/h

(ii) m/s.= 24600/ 1800= 13.66 m/s

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A production system has a total daily output of 400 units and a total labor of 350 hours, what kind of productivity measure can

fomenos

Answer:

1.14 products per hour of labor

Step-by-step explanation:

To calculate the daily productivity would be the amount of products per hour of labor.

That is: 400 products / 350 hours of labor, and that is approximately 1.14 products per hour of labor.

Which means that for every hour of labor, 1.14 products are produced in one day, which would be a factor of productivity.

4 0

2 years ago

Natasha is seeding her backyard. The backyard is square in shape and has an area of 4225 square feet. What is the length of one

N76 [4]

Answer:65ft

Step-by-step explanation:area of a square is =s^2

Therefore 4225=s^2

Find the square root of both sides

√4225=√s^2

Therefore s=65

Each side is 65ft

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2 years ago

A man is in a boat that is floating 175 feet from the base of a 200 foot cliff. What is the angle of depression between the clif

LUCKY_DIMON [66]

Answer:

The of depression between the cliff and the boat is 48.74 degrees.

Step-by-step explanation:

We have,

Height of the cliff is 200 foot

Distance of boat from the cliff is 175 feet

It is required to find the angle of depression between the cliff and the boat.

Here, 200 foot is perpendicular distance and 175 is base.

Using trigonometry :

$\tan\theta=\dfrac{P}{B}\\\\\tan\theta=\dfrac{200}{175}\\\\\theta=\tan^{-1}(1.14)\\\\\theta=48.74^{\circ}$

So, the of depression between the cliff and the boat is 48.74 degrees.

8 0

2 years ago

What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0? Use u substitution and the quadratic formula to solve.

zvonat [6]

Answer:

$x=-2.38$

$x=-4.62$

Step-by-step explanation:

The question is $(2x+3)^2+8(2x+3)+11=0$

We let $u=2x+3$ , so the equation becomes:

$u^2+8u+11=0$

Where $a=1, b=8, c=11$

Putting it in the quadratic formula, we have:

Quadratic formula: $\frac{-b+-\sqrt{b^2-4ac} }{2a}$

Substituting we have: $\frac{-8+-\sqrt{(8)^2-4(1)(11)} }{2(1)}\\=\frac{-8+-\sqrt{20} }{2}\\=\frac{-8+-2\sqrt{5} }{2}\\=-4+\sqrt{5}, -4-\sqrt{5} }$

We let $u=2x+3$ , so x is:

$u=2x+3\\(-4+\sqrt{5})=2x+3\\x=\frac{-7+\sqrt{5}}{2}=-2.38$

and

$u=2x+3\\(-4-\sqrt{5})=2x+3\\x=\frac{-7-\sqrt{5}}{2}=-4.62$

The solutions of the equation is $x=-2.38$ (rounded to 2 decimal places), and $x=-4.62$ (rounded to 2 decimal places)

6 0

2 years ago

Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a)

Salsk061 [2.6K]

Answer:

a) 1 tsp.

b) 1.5 tsp.

c) 2 tsp.

Step-by-step explanation:

Complete Correct Question

Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a) a 18 kg adult dog (b) a 6 kg cat (c) 18 kg pregnant dog

- The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.

- The dosage listed for adult cat is 1/4 tsp per 1 kg weight.

- The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.

Solution

a) 18 kg adult dog

The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.

9 kg dog weight = (1/2) tsp

18 kg adult dog = (18/9) × (1/2) = 1 teaspoon.

b) 6 kg cat

The dosage listed for adult cat is 1/4 tsp per 1 kg weight.

1 kg cat = (1/4) tsp

6 kg cat = (6/1) × (1/4) = (6/4) = 1.5 teaspoons.

c) 18 kg pregnant dog

The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.

4.5 kg dog weight = (1/2) tsp

18 kg pregnant dog = (18/4.5) × (1/2) = 2 teaspoons.

Hope this Helps!!!

4 0

2 years ago

Read 2 more answers