Adjust point D so the measure of angle BAD is equal to the measure of angle CAD. Which statements are true? Check all that apply
. AD bisects ∠BAC. AD bisects BC. AD forms right angles with BC. AD is perpendicular to BC. AD is the perpendicular bisector of BC.
2 answers:
Answer with explanation:
it is given that ,in ΔABC,
∠BAD=20°, and ∠CAD=54°
We have to adjust point D,so that measure of angle BAD is equal to the measure of angle CAD.
that is, if point D is moved to right of B,then ∠BAD increases from 20° to (20+x)° and ∠CAD decreases from 54° to (54-x)°.
→20 +x=54-x
⇒ 2 x= 54 -20
⇒2 x=34
x=17°
Using angle bisector theorem, if AD bisects ∠B AC.
so,
If, ∠BAD=∠CAD=37°, then
1. AD bisects ∠B AC.→→→Option A
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Complete Question
The complete question is shown on the first uploaded image
Answer:
a
The probability that he or she would choose the pair of socks in the center position is
The correct answer choice is
X has a binomial distribution with parameters n=100 and p=1/5
b
The mean is
The standard deviation is
c
The probability,
d
The correct answer is
The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.
Using the R the probability
The probabilities
Step-by-step explanation:
Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as
The mean of this distribution is mathematical represented as
substituting the value
The standard deviation is mathematically represented as
substituting the value
Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as
By standardizing the normal approximation we have that
Now z is mathematically evaluated as
Substituting values
So using the z table the is 0.0002
The probability P and Pe that 34 or more subject would choose the center pair is very small So
The correct answer is
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