Adjust point D so the measure of angle BAD is equal to the measure of angle CAD. Which statements are true? Check all that apply
. AD bisects ∠BAC. AD bisects BC. AD forms right angles with BC. AD is perpendicular to BC. AD is the perpendicular bisector of BC.
2 answers:
Answer with explanation:
it is given that ,in ΔABC,
∠BAD=20°, and ∠CAD=54°
We have to adjust point D,so that measure of angle BAD is equal to the measure of angle CAD.
that is, if point D is moved to right of B,then ∠BAD increases from 20° to (20+x)° and ∠CAD decreases from 54° to (54-x)°.
→20 +x=54-x
⇒ 2 x= 54 -20
⇒2 x=34
x=17°
Using angle bisector theorem, if AD bisects ∠B AC.
so,
If, ∠BAD=∠CAD=37°, then
1. AD bisects ∠B AC.→→→Option A
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Answer:
AB = DC
Step-by-step explanation:
Applying the information provide in the attached diagram , The statement that can deduce the line segments to be parallel is : AB = DC
when M2 = M3
attached below is the missing diagram as related to this question above
Answer:
The triangular prism shown has 2 triangular face(s) and 3 lateral face(s).
The area of one triangular face is 7.5 mm²
The surface area of the triangular prism is 135 mm²
Step-by-step explanation:
A triangular face of the prism is the face that has a three sided figure while the lateral faces are faces with four-sided figure. As seen from the triangular prism, it has 2 triangular faces since it is made up of 2 right angled triangles and has 3 lateral faces since it is made up of 3 rectangles which are 4 sided each.
Area of one triangular face =
Given base = 2.5 mm and height = 6 mm
Area of one triangular face =
Surface area of triangular prism = bh + pH
b= base of the triangle = 2.5 mm
h- height of the triangle = 6 mm
p= perimeter of the triangle = base + height + slant height = 2.5+6+6.5
p = 15 mm
H= height of the prism = 8mm
Surface area of triangular prism = 2.5(6)+15(8)
Surface area of triangular prism = 15 + 120
Surface area of triangular prism = 135mm²
