Answer: The distance between the girls is 362.8 meters.
Step-by-step explanation:
So we have two triangle rectangles that have a cathetus in common, with a length of 160 meters.
The adjacent angle to this cathetus is 40° for Anna, then the opposite cathetus (the distance between Anna and the tower) can be obtained with the relationship:
Tan(A) = opposite cath/adjacent cath.
Tan(40°) = X/160m
Tan(40°)*160m = 134.3 m
Now, we can do the same thing for Veronica, but in this case the angle adjacent to the tower is 55°
So we have:
Tan(55°) = X/160m
Tan(55°)*160m = X = 228.5 m
And we know that the girls are in opposite sides of the tower, so the distance between the girls is equal to the sum of the distance between each girl and the tower, then the distance between the girls is:
Dist = 228.5m + 134.3m = 362.8m
Theres not really a way to show that on here unless i draw you a picture...you must know that 10 thousandths is equal to 1 hundredth. if you draw a 100 by 100 centimeter square on graph paper it will consist of a thousand squares since 100 x 100 is 1000, and if you colored in 10 of those squares, it would be 10 thousandths
Answer: The correct option is A, itis the product of the initial population and the growth factor after h hours.
Explanation:
From the given information,
Initial population = 1000
Increasing rate or growth rate = 30% every hour.
No of population increase in every hour is,
Total population after h hours is,
It is in the form of,
Where 
is the initial population, r is increasing rate, t is time and [tex(1+r)^t[/tex] is the growth factor after time t.
In the above equation 1000 is the initial population and 
is the growth factor after h hours. So the equation is product of of the initial population and the growth factor after h hours.
Therefore, the correct option is A, itis the product of the initial population and the growth factor after h hours.
We are given
v = 18 m/hr west
θ1 = 285°
θ2 = 340°
After 1 hours, the distance traveled by the ship is
dv = 18 mi
The distance between the ship and the lighthouse is
d = 18 / cos 340
Solve for d<span />
Answer:
m∠FJH=60°
Step-by-step explanation:
The complete question is
JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)°
What is FJH
we know that
m∠FJH=m∠FJG+m∠GJH -----> equation A
If ray JG is an angle bisector of ∠FJH
then
m∠FJG=m∠GJH -----> equation B
substitute the given values in equation B and solve for x
(2x + 4)°=(3x -9)°
3x-2x=4+9
x=13
Find the measure of angle FJH
m∠FJH=(2x + 4)°+(3x -9)°
substitute the value of x
m∠FJH=(2(13) + 4)°+(3(13) -9)°
m∠FJH=(30)°+(30)°
m∠FJH=60°
