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PtichkaEL [24]
2 years ago
8

What is the volume of a 90' x 20' x 12' house?

Mathematics
2 answers:
inysia [295]2 years ago
6 0

Answer:

The volume of the house is 2.2 × 10⁴ ft³.

Step-by-step explanation:

The dimensions of a house are:

  • Side 1 (s₁): 90 ft
  • Side 2 (s₂): 20 ft
  • Side 3 (s₃): 12 ft

If we consider the house to be a cuboid, we can find its volume (V) using the following expression.

V = s₁ × s₂ × s₃

V = 90 ft × 20 ft × 12 ft

V = 2.2 × 10⁴ ft³

The volume of the house is 2.2 × 10⁴ ft³.

mafiozo [28]2 years ago
5 0
21,600 v^3 been a while so not sure wether you need the sq symbol afterword let me know
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Evaluate y = ln (x − 2) for the following values of x. Round to the nearest thousandth.
MatroZZZ [7]

Answer:

0

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Step-by-step explanation:

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Your last five customer interactions lasted 2,3,6,8 and 4minutes how many minutes did i average across the 5
Phantasy [73]
So to find the avrage u r going to add all the numbers then divide by the nuber of nubers u have there  that will give u ur answer

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What are the factors of the polynomial function? Use the rational root theorem to determine the factors. f(x) = 2x³ + x² - 8x -
fredd [130]

Answer:

( x + 2 ) ( x - 2 ) ( 2x + 1)

Step-by-step explanation:

coefficient of x³ is 2 and denote it with q and denote -4 as p

the set of possible rational roots through rational theorem will be within ± (p/q)

now factors of -4 are ±(1,2,4) and factors of 2 are ± (1,2) the possible rational roots are ± ( 1/1, 1/2, 2/1, 2/2, 4/1, 4/2) which reduces to ± (1, 1/2, 2, 4)

substitute each of the value into the equation

f(x) = 2x³ + x² - 8x - 4 to the root ( that gives f(x) = 0)

the equation can be made easy writing it in reduced form

2x³ + x² - 8x - 4

(2x³ + x²) - (8x + 4)

x² (2x + 1) - 4 (2x + 1)

(x² - 4) (2x + 1)

( x + 2 ) ( x - 2) ( 2x + 1) are the factors which correspond to 2, -2, -1/2 roots

4 0
2 years ago
Royce is folding a piece of paper to make an origami figure. Each time he folds the paper, the thickness of the paper is doubled
Alisiya [41]
The input value is the number of times you fold it. The input value is also known as the x-value. 
The output value is its thickness. The output value is the y-value.

When you don't fold it all, the thickness will remain the same, which is 2. The ordered pair would be (0, 2).

When you fold it once, the thickness will double from 2 to 4. The ordered pair would be (1,4).

When you fold it a second time, the thickness will double from 4 to 8. The ordered pair would be (2,8).

Fold it one more time, and the thickness will be 16. The ordered pair is (3,16)

Fold it the fourth time, and the thickness doubles. 16 x 2 = 32 The ordered pair is (4, 32)

Fold it the fifth time, and the thickness goes from 32 to 64. The ordered pair is (5,64)

The ordered pairs would be:
(0,2)
(1,4)
(2,8)
(3,16)
(4,32)
(5,64)
(6,128)
(7,256)
and so on :P

The question asks for 6 ordered pairs, so I bolded the first six.

Now, the equation for this would be y = 2^{(x+1)}

If we graph that, and we do the vertical line test, then we know this is a function.

It is a function because each x-value has a different y-value. There are no y-values that have the same x-values.

<span>I have attached the graph of that line.</span>

6 0
2 years ago
A parallelogram whose vertices have coordinates R(1, -1), S(6, 1), T(8, 5), and U(3, 3) has a shorter diagonal of ___ . 5 √(13)
butalik [34]

Answer:

|SU|=\sqrt{13}

Step-by-step explanation:

The given parallelogram has vertices R(1, -1), S(6, 1), T(8, 5), and U(3, 3) .

Recall the distance formula;

We use the distance formula to determine the length of the diagonals.

For diagonal R(1,-1) and T(8,5), We have;

|RT|=\sqrt{(8-1)^2+(5--1)^2}

|RT|=\sqrt{(7)^2+(6)^2}

|RT|=\sqrt{49+36}

|RT|=\sqrt{85}

For the diagonal S(6,1) U(3,3)

|SU|=\sqrt{(6-3)^2+(5-3)^2}

|SU|=\sqrt{(3)^2+(2)^2}

|SU|=\sqrt{9+4}

|SU|=\sqrt{13}

Therefore the shorter diagonal is:

|SU|=\sqrt{13}

4 0
1 year ago
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