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olga2289 [7]
2 years ago
10

Ty had 10 eggs. He made 4 servings of scrambled eggs. He used n eggs for each serving.

Mathematics
1 answer:
Rzqust [24]2 years ago
6 0

10-4n=x

Hope this helps.

Brainliest would help me as well.

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Which geometric object is defined as the set of all points in a plane equidistant from a single point and a single line?
Reptile [31]

Answer: parabola

Step-by-step explanation:

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2 years ago
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La hormiguita Fidencia se encontro una hojita, la cargo y se llevo al hormiguero. Le dio a su amiguita 1/5 y ella se comió 1/3 d
vredina [299]

Answer:

The ant Fidencia ate more

Step-by-step explanation:

The question in English

The ant Fidencia found a leaf, the charge and took the anthill. She gave her friend 1/5 and she ate 1/3 of the leaf. Who ate more?

Her friend

Multiply (1/5) by (3/3)

(1/5)*(3/3)=3/15

Ant Fidencia

Multiply (1/3) by (5/5)

(1/3)*(5/5)=5/15

Compare

5/15 > 3/15 -----> two fractions with the same denominator the fraction with the highest numerator is greater

therefore

The ant Fidencia ate more

7 0
2 years ago
If 20% of all manually filed returns contain errors, and 0.05% of all electronically filed returns contain errors, how much more
Marizza181 [45]
To get the correct answer to this question, you just need to divide 20% by 0.05% in order to get the answer, how many times a manual filer is more likely to make an error than an electronic file. 
20: 0.05 = 400
The answer is C. 400 times more likely.
4 0
2 years ago
Are triangles ADC and EBC congruent? triangle ADC is overlapping triangle EBC so that they both share angle ACE, point B is on s
Olin [163]

Answer:

Yes, by AAS ⇒ 2nd answer

Step-by-step explanation:

* <em>Lets revise the cases of congruence</em>

- <u><em>SSS</em></u>  ⇒ 3 sides in the 1st Δ ≅ 3 corresponding sides in the 2nd Δ  

- <u><em>SAS</em></u> ⇒ 2 sides and including angle in the 1st Δ ≅ 2 corresponding

 sides and   including angle in the 2nd Δ  

- <u><em>ASA</em></u> ⇒ 2 angles and the side whose joining them in the 1st Δ   ≅

 2 corresponding angles and the side whose joining them in the 2nd Δ  

- <em><u>AAS</u></em> ⇒ 2 angles and one side in the first triangle ≅ 2 corresponding

 angles   and one side in the 2ndΔ

* <em>Lets solve the problem</em>

- In 2 Δs ADC and EBC

∵ <em>∠ACE is a common angle</em> in the two triangles ⇒ given

∵ <em>∠CAD ≅ ∠CEB</em> ⇒ because they marked with the same symbol

∵ <em>DC ≅ BC</em> ⇒ because they marked with the same symbol

- Two angles and one side in Δ ADC ≅ two corresponding angles  

  and one side in Δ EBC

∴ <u><em>Triangles ADC and EBC congruent by AAS</em></u>

* Yes Triangles ADC and EBC congruent by AAS

8 0
2 years ago
Read 2 more answers
Bonzo went to a carnival. At the first
Shalnov [3]

Bonzo started with 2.1 dollars

Step-by-step explanation:

Assume that Bonzo has $x

1. Change $x to cents

2. Calculate the remaining money with him after each game

3. Equate the left money in the 3rd game by zero to find x

∵ $1 = 100 cents

∴ $x = 100 x cents

First game

∵ Bonzo has 100 x cents

∵ He paid 10¢ to get in

∴ The money left is (100 x - 10)

∵ He spent half  the money he had left

- That mean the money left with him is the other have

∴ The money left with him = \frac{1}{2} (100 x - 10) = (50 x - 5) cents

∵ He spent 10¢  to get out

∴ The money left after 1st game = (50 x - 5) - 10

∴ The money left after 1st game = (50 x - 15) cents

Second game

∵ Bonzo has (50 x - 15) cents

∵ He paid 10¢ to get in

∴ The money left is (50 x - 15) - 10 = (50 x - 25)

∵ He spent half  the money he had left

∴ The money left with him = \frac{1}{2} (50 x - 25) = (25 x - 12.5) cents

∵ He spent 10¢  to get out

∴ The money left after 2nd game = (25 x - 12.5) - 10

∴ The money left after 2nd game = (25 x - 22.5) cents

Third game

∵ Bonzo has (25 x - 22.5) cents

∵ He paid 10¢ to get in

∴ The money left is (25 x - 22.5) - 10 = (25 x - 32.5)

∵ He spent half  the money he had left

∴ The money left with him = \frac{1}{2} (25 x - 32.5) = (12.5 x - 16.25) cents

∵ He spent 10¢  to get out

∴ The money left after 3rd game = (12.5 x - 16.25) - 10

∴ The money left after 3rd game = (12.5 x - 26.25) cents

∵ He found he had no money left after the 3rd game

∴ Equate the left money with him by zero

∴ 12.5 x - 26.25 = 0

- Add 26.25 to both sides

∴ 12.5 x = 26.25

- Divide both sides by 12.5

∴ x = 2.1

<em>Bonzo started with 2.1 dollars </em>

Learn more:

You can learn more about money in  brainly.com/question/1870710

#LearnwithBrainly

5 0
2 years ago
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