Answer:
(a) The standard deviation of your waiting time is 4.33 minutes.
(b) The probability that you will have to wait more than 2 standard deviations is 0.4227.
Step-by-step explanation:
Let <em>X</em> = the waiting time for the bus at the parking lot.
The random variable <em>X</em> is uniformly distributed with parameters <em>a</em> = 0 to <em>b</em> = 15.
The probability density function of <em>X</em> is given as follows:

(a)
The standard deviation of a Uniformly distributed random variable is given by:

Compute the standard deviation of the random variable <em>X</em> as follows:




Thus, the standard deviation of your waiting time is 4.33 minutes.
(b)
The value representing 2 standard deviations is:

Compute the value of P (X > 8.66) as follows:





Thus, the probability that you will have to wait more than 2 standard deviations is 0.4227.
Answer:
eliminated, the bedtime increases by one minute. ... Description: This activity requires students to tell time to the half-hour (e.g. 4:00, 5:30, 11:30).
Step-by-step explanation:
K(-1+1.01)+0.03=-2.45-1.81k
0.01k+1.81k=-0.03-2.45
1.82k=-2.42
k=-2.45\1.82=1.3
Answer:
Kenji counted by One fifth instead of three fifths.
Step-by-step explanation:
When you count by one fifths to equal the 9/10 then you would get 4 1/2 as an answer. the answer is counting by three fifths to equal 1 1/2.
Answer:
procedure always produces 6
Step-by-step explanation:
Let 'n' be the unknown number
Add 4 to the number : n+4
multiply the sum by 3.
multiply the sum n+4 by 3

Now subtract 6, so we subtract 6 from 3n+12

finally decrease the difference by the tripe of the original number
triple of original number is 3n

so the procedure always produces 6