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I am Lyosha [343]
2 years ago
15

The linearized regression equation for an exponential data set is log ŷ = 0.14x + 0.4, where x is the number of years and y is t

he population. What is the predicted population when x = 15? Round your answer to the nearest whole number.
A.3
B.126
C.316
D.9537
Mathematics
1 answer:
djyliett [7]2 years ago
7 0

Option C: 316 is the predicted population when x=15

Explanation:

The regression equation for an exponential data is \log y=0.14x+0.4

Where x is the number of years and

y is the population

We need to determine the predicted population when x=15

The population x can be determined by substituting x=15 in the equation \log y=0.14x+0.4

Thus, we have,

\log y=0.14(15)+0.4

\log y=2.1+0.4

\log y=2.5

Using the logarithmic definition \log _{a}(b)=c then b=a^{c}

\log _{10}(y)=2.5 \Rightarrow y=10^{2.5}

y=316.22776 \ldots

Rounding off to the nearest whole number, we get,

y=316

Thus, the predicted population when x=15 is 316

Hence, Option C is the correct answer.

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Answer:

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Where X represents the number of dollars won during the flip of the coin, probability of heads represent the chances of occurrence of the value and of winning the dollars.

The probability of winning start to drop as the winning amount increases.

       

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Probability of Heads  0 0.50 0.25 0.13    0.06 0.03

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Milton spilled some ink on his homework paper. He can't read the coefficient of $x$, but he knows that the equation has two dist
Lera25 [3.4K]

Answer:

Sum = -81

Step-by-step explanation:

See the comment for complete question.

Given

c = 36 ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

36 ---- constant

So, the equation can be represented as:

x^2 + ax + 36 = 0

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

x = -\alpha and x = -\beta

Using the above roots, the equation can be represented as:

(x + \alpha)(x + \beta) = 0

Open brackets

x^2 + (\alpha + \beta)x + \alpha \beta = 0

To compare the above equation to x^2 + ax + 36 = 0, we have:

a = \alpha + \beta

\alpha \beta = 36

Where: \alpha, \beta and \alpha \ne \beta

The values of \alpha and \beta that satisfy \alpha \beta = 36 are:

\alpha = -1 and \beta = -36

\alpha = -2 and \beta = -18

\alpha = -3 and \beta = -12

\alpha = -4 and \beta = -9

So, the possible values of a are:

a = \alpha + \beta

When \alpha = -1 and \beta = -36

a = -1 - 36 = -37

When \alpha = -2 and \beta = -18

a = -2 - 18 = -20

When \alpha = -3 and \beta = -12

a = -3 - 12 = -15

When \alpha = -4 and \beta = -9

a = -4 - 9 = -13

At this point, we have established that the possible values of a are: -37, -20, -15 and -9.

The required sum is:

Sum = -37 -20 -15 - 9

Sum = -81

7 0
2 years ago
What is the GCF of x2 and x9?​
zepelin [54]

Answer:

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Step-by-step explanation:

Given the values x² and x^9

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Factors of :

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Multiplying the Factors in both are : x * x = x²

Similarly :

___|x² | x^9

_ x | x | x^8

_ x | 1 | x^7

There is no factor which can reduce both further simultaneously, Hence the G. C. F = (x * x) = x²

3 0
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