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Veseljchak [2.6K]
1 year ago
9

Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?

Mathematics
2 answers:
MrMuchimi1 year ago
7 0

Answer:

the answer is A on edgenuaty

Step-by-step explanation:


AleksAgata [21]1 year ago
4 0

we are given

12x^3-2x^2+18x-3

Firstly, we will split terms

2x^2*6x-1*2x^2+3*6x-1*3

We can group first two and last two terms

(2x^2*6x-1*2x^2)+(3*6x-1*3)

we can see that 2x^2 is common in first two terms

and 3 is common in last two terms

so, we can factor factor out 2x^2 from first group and 3 from second group

we get

=2x^2(6x-1)+3(6x-1)

we can see that each terms are multiple of 6x-1

so, we can factor out 6x-1

so, we get

12x^3-2x^2+18x-3 =(2x^2+3)(6x-1)............Answer


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