Question

Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?

Answer 1

Answer:

the answer is A on edgenuaty

Step-by-step explanation:

Answer 2

we are given

$12x^3-2x^2+18x-3$

Firstly, we will split terms

$2x^2*6x-1*2x^2+3*6x-1*3$

We can group first two and last two terms

$(2x^2*6x-1*2x^2)+(3*6x-1*3)$

we can see that 2x^2 is common in first two terms

and 3 is common in last two terms

so, we can factor factor out 2x^2 from first group and 3 from second group

we get

$=2x^2(6x-1)+3(6x-1)$

we can see that each terms are multiple of 6x-1

so, we can factor out 6x-1

so, we get

$12x^3-2x^2+18x-3 =(2x^2+3)(6x-1)$............Answer