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soldi70 [24.7K]
2 years ago
13

Line z has a slope of 2.5 and goes through point (4, 13). Which equation best represents line z?​

Mathematics
1 answer:
Rus_ich [418]2 years ago
7 0

Answer:

y - 13 = (5/2)(x - 4)

Step-by-step explanation:

Here we know the slope and one point on the line.  Use the point-slope formula:

y - k = m(x - h).

Substituting 13 for k, 4 for x and 2.5 for m, we get:

y - 13 = (5/2)(x - 4)\

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Using Normal Distribution to Analyze Data Martin suspects that people carry less cash with them than they used to because of cre
jek_recluse [69]

Answer:

Step-by-step explanation:

Sample size = 95

X=cash carried by the persons

x bar = 8.00

s = sample std dev = 2.50

Std error = \frac{s}{\sqrt{n} } =\frac{2.5}{\sqrt{95} } \\=0.2565

Hence Z score would be

\frac{x-8}{0.2565}

a) P(X

-0.00

b) P(9

c) 95% conf interval margin of error = ±1.96*0.2565

=±0.54782

Confi interval = (8-0.5027, 8+0.5027)

= (7.4923, 8.5027)

C)If conf level increases, then width of interval would increase since critical value would increase.

If sample size increases std error would decrease and hence margin of error.

So interval would decrease.

3 0
2 years ago
Zane and Matt are both keen runners. Zane takes 4 minutes to jog around a running track and Matt takes 5 minutes. They start at
Sergio [31]
I believe that the correct answer to this question is B. because matt took more than 5 minutes .
3 0
2 years ago
A candle is a square prism. The candle is 15 centimeters high, and its volume is 960 cubic centimeters. a) Find the length of ea
Yakvenalex [24]

Answer:

a] is 8cm

Step-by-step explanation:

A=2a2+4ah

a=8cm

h=15cm

therefore A=608

3 0
2 years ago
Sin(11∘)cos(19∘)+cos(11∘)sin(19∘)
sergij07 [2.7K]
Recall that:

sin(A + B) = sinAcosB + cosAsinB

Therefore:

sin11°cos19° + cos11°sin19° = sin(11° + 19°)

                                                   = sin30° = 0.5            

I hope this explains it.
3 0
2 years ago
Find the solution set of the following equations: <br><br>2y=2x+7<br><br>X=y+2
kirill115 [55]

Answer:

The system of equations has no solution.

Step-by-step explanation:

Given the system of equations

2y = 2x+7

x = y+2

solving the system of equations

\begin{bmatrix}2y=2x+7\\ x=y+2\end{bmatrix}

Arrange equation variables for elimination

\begin{bmatrix}2y-2x=7\\ -y+x=2\end{bmatrix}

Multiply -y+x=2 by 2:  -2y+2x=4

\begin{bmatrix}2y-2x=7\\ -2y+2x=4\end{bmatrix}

so adding

-2y+2x=4

+

\underline{2y-2x=7}

0=11

so the system of equations becomes

\begin{bmatrix}2y-2x=7\\ 0=11\end{bmatrix}

0 = 11 is false, therefore the system of equations has no solution.

Thus,

No Solution!

3 0
2 years ago
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