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LuckyWell [14K]
2 years ago
12

A store sold a certain brand of jeans for $38 one day, the store sold 6 pair of jeans of that brand. How much did the 6 pairs of

jeans cost?
Mathematics
2 answers:
denis-greek [22]2 years ago
5 0
228 Because 38 x 8 = 228.
 
4
 38
x 6
____

228


baherus [9]2 years ago
4 0
6 pairs of jeans would cost $228.
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You deposit $2,900 into a bank account with a simple interest rate of 10% how do you find your account balance after 5 years
MAVERICK [17]
Formula: A = P(1 + rt)<span>
P= 2,900
R= 10%
T= 5 years 

Answer: $4,350.00</span>
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Dominic earns $285 per week plus an 8% commission rate on all his sales. If Dominic sells $4,213 worth of merchandise in one wee
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(4213*.08)+285=
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2 years ago
What is the yyy-intercept of y=-3-7xy=−3−7xy, equals, minus, 3, minus, 7, x?
stiv31 [10]

<em><u>Complete Question:</u></em>

What is the y intercept of y = -3-7x

<em><u>Answer:</u></em>

<h3>The y intercept is (0, -3)</h3>

<em><u>Solution:</u></em>

<em><u>Given equation is:</u></em>

y = -3 - 7x

The y intercept is the point where the line crosses the y axis

<u>Finding y intercept: </u>

To determine the y-intercept, we set x equal to zero and solve for y

Substitute x = 0 in given equation

y = -3 - 7(0)

y = -3 - 0

y = -3

Thus the y intercept is (0, -3)

8 0
2 years ago
Describe how you regroup when you find the sum of 64 + 43
vaieri [72.5K]
When you regroup you are basically breaking down the problem.
You would do 60 + 40=?
Then you would do 4 + 3= ?
Your answer would come out to 107
4 0
2 years ago
An ostrich can run 6 mph faster than a giraffe. An ostrich can run 7 miles in the same time that a giraffe can run 6 miles. Find
LUCKY_DIMON [66]

NOTE THIS IS AN EXAMPLE:

Let t = time, s = ostrich, and g = giraffe.

Here's what we know:

s = g + 5 (an ostrich is 5 mph faster than a giraffe)

st = 7 (in a certain amount of time, an ostrich runs 7 miles)

gt = 6 (in the same time, a giraffe runs 6 miles)

 

We have a value for s, so plug it into the first equation:

(g + 5)t = 7

gt = 6

 

Isolate g so that we can plug that variable value into the equation:

g = 6/t

so that gives us:

(6/t + 5)t = 7

Distribute:

6 + 5t = 7

Subtract 6:

5t = 1

Divide by 5:

t = 1/5 of an hour (or 12 minutes)

 

Now that we have a value for time, we can plug them into our equations:

1/5 g = 6

multiply by 5:

g = 30 mph

 

s = 30 + 5

s = 35 mph

 

Check by imputing into the second equation:

st = 7

35 * 1/5 = 7

7 = 7

5 0
2 years ago
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