Given :
A carton of 12 eggs or a carton of 18 eggs was the better buy. A carton of 12 eggs cost $2.39, and a carton of 18 eggs cost $3.39. Unit price of the 12-egg carton = ($2.39)(12 eggs) = $28.68 per egg Unit price of the 18-egg carton = ($3.39)(18 eggs) = $61.02 per egg The 12-egg carton has the lower unit cost, so it is the better buy.
To Find :
What was her first error.
Solution :
Her first error is to find Unit price of egg in each carton.
To find, unit price we should divide total amount by number of units :
Unit price for carton of 12 eggs, $ (2.39)/12 = $0.199 .
Hence, this is the required solution.
Answer:
$24166.67
Step-by-step explanation:
$25 per hour and works 35 hours per week
Norma Jean makes 35 * 25 (<em>without sales) = </em>$875
<em> </em>Total commission made by Norma<em> </em>= 4500-875 = $3625
<em>let total number of sales by Norma be x</em>
15% is the same as 15/100
<em>so </em>(15/100) * x =3625 <em> multiplying both sides by 100</em>
15x = 362500<em> making x subject of formula</em>
x = 362500/15
x = 24 166.67
Norma should sell total items worth $24166.67
Answer:
a) 5.5
b) None
Step-by-step explanation:
The given data set is {96,89,79,85,87,94,96,98}
First we must find the mean.

We now find the absolute value of the distance of each value from the mean.
This is called the absolute deviation
{
}
{
}
We now find the mean of the absolute deviations

The least absolute deviation is 1.5. This is not within one absolute deviation.
Therefore none of the data set is closer than one mean absolute deviation away from the mean.
Answer:
A and C
Step-by-step explanation:
To determine which events are equal, we explicitly define the elements in each set builder.
For event A
A={1.3}
for event B
B={x|x is a number on a die}
The possible numbers on a die are 1,2,3,4,5 and 6. Hence event B is computed as
B={1,2,3,4,5,6}
for event C
![C=[x|x^{2}-4x+3]\\solving x^{2}-4x+3\\x^{2}-4x+3=0\\x^{2}-3x-x+3=0\\x(x-3)-1(x-3)=0\\x=3 or x=1](https://tex.z-dn.net/?f=C%3D%5Bx%7Cx%5E%7B2%7D-4x%2B3%5D%5C%5Csolving%20%20x%5E%7B2%7D-4x%2B3%5C%5Cx%5E%7B2%7D-4x%2B3%3D0%5C%5Cx%5E%7B2%7D-3x-x%2B3%3D0%5C%5Cx%28x-3%29-1%28x-3%29%3D0%5C%5Cx%3D3%20or%20x%3D1)
Hence the set c is C={1,3}
and for the set D {x| x is the number of heads when six coins re tossed }
In the tossing a six coins it is possible not to have any head and it is possible to have head ranging from 1 to 6
Hence the set D can be expressed as
D={0,1,2,3,4,5,6}
In conclusion, when all the set are compared only set A and set C are equal