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PolarNik [594]
2 years ago
6

PLEASE ANSWER! IM DESPERATE PLEASE;;

Mathematics
1 answer:
harkovskaia [24]2 years ago
4 0

Answer:

1. 8c^2 + 24c - 6

2. B

3. 4 and 3

4. -90cd 168c3d -30c2

Step-by-step explanation:

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Answer:

The following are the answer to this question:

Step-by-step explanation:

In the given question the numeric value is missing which is defined in the attached file please fine it.  

Calculating the probability of the distribution for x:

\to f(x) = 0.19\  for \ x=14\\\\\to  f(x) = 0.29 \ for\ x=7\\\\\to f(x) = 0.38\  for \ x=1\\\\\to f(x)=0.14 \ for \ x=0\\

The formula for calculating the mean value:

\bold{ E(X)= x \times f(x)}

          =14 \times 0.19+7 \times 0.29+1 \times 0.38+0\times 0.14\\\\=2.66 + 2.03+0.38+ 0\\\\=5.07

\bold{E(X^2) = x^2 \times f(x)}

           =14^2 \times 0.19+7^2 \times 0.29+1^2 \times 0.38+0^2 \times 0.14 \\\\=196 \times 0.19+ 49 \times 0.29+1 \times 0.38+0 \times 0.14\\\\= 37.24+ 14.21+ 0.38+0 \\\\=51.83

use formula for calculating the Variance:

\to \bold{\text{Variance}= E(X^2) -[E(X)]^2}

                  = 51.83 - (5.07)^2\\\\= 51.83 -  25.70\\\\=26.13

calculating the value of standard deivation:

Standard Deivation (SD) = \sqrt{Variance}

                                          = \sqrt{26.13} \\\\=5.111

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The weight of people in a small town in missouri is known to be normally distributed with a mean of 154 pounds and a standard de
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If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
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