wingspans of adult herons have approximate normal distribution with mean 125cm and a standard deviation 12cm. what proportion of
1 answer:
Answer:
Step-by-step explanation:
We know that the heron wingspan follow a normal distribution with an mean of 125 cm.
In this case we seek to find
If X is a random variable that represents the length of the heron wingspan, then X follows a normal distribution and therefore is a continuous random variable.
Then by definition of continuous random variable we have to:
where a is a constant.
That is to say that only the ranges of values can have a different probability of zero. The probability that a continuous random variable is equal to some exact value is always zero.
Finally we can conclude that
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1.The isosceles triangle has sides of length 14, y, y
2. According to the "triangle inequality" :
y+y>14
2y>14
y>14/2=7
(y is greater than 7)
3. Remark, check the figures:
the side lengths cannot be less than (neither equal to 7), because we cannot get a triangle in that case, check picture 2
In picture 1 wee see that the side lengths can be as large as we want. We can erect an altitude, as high as we want. Pick a point on the altitude, and join it to the endpoints of the base, and we get an isosceles triangle with base equal to 14.
2. According to the "triangle inequality" :
y+y>14
2y>14
y>14/2=7
(y is greater than 7)
3. Remark, check the figures:
the side lengths cannot be less than (neither equal to 7), because we cannot get a triangle in that case, check picture 2
In picture 1 wee see that the side lengths can be as large as we want. We can erect an altitude, as high as we want. Pick a point on the altitude, and join it to the endpoints of the base, and we get an isosceles triangle with base equal to 14.