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nikdorinn [45]
1 year ago
11

Carey creates the table below to help him determine 75% of 36. 75% of 36 25% 25% 25% 25% One-fourth One-fourth One-fourth One-fo

urth 9 9 9 9 He writes the expression (three-fourths) (27). Which change in Carey’s expression will lead him to the correct answer? The 27 could be changed to 36. The Three-fourths could be changed to One-fourth. The Three-fourths could be changed to One-fourth, and the 27 could be changed to 9. The 27 could be changed to 36, and the Three-fourths could be changed to One-fourth.
Mathematics
2 answers:
alina1380 [7]1 year ago
7 0

Answer:

The correct option is (A).

Step-by-step explanation:

The expression Carey is solving is:

X=75\%\ \text{of}\ 36

Simplify the expression as follows:

X=75\%\ \text{of}\ 36

   =\frac{75}{100}\times 36\\\\=\frac{3}{4}\times 36\\\\=3\times 9\\\\=27

So, in Carey's calculation the third step is incorrect.

Instead of 27 the three-fourth must be multiplied by 36 to get the correct answer.

Thus, the correct option is (A).

satela [25.4K]1 year ago
6 0

Answer:

option A.The 27 could be changed to 36.

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H is directly proportional to the square root of p h= 5.4 when p = 1.44 find h when p =2.89
LenKa [72]

Answer:

h=7.65

Step-by-step explanation:

H is directly proportional to the square root of p;

Let k be the constant of proportionality;

Means h=k√p

This means for corresponding points of h and p such that (h1,p1) and (h2,p2) we have;

h1/√p1=h2/√p2

Let h= 5.4 when p = 1.44 and h when p =2.89 be respectively (h1,p1) and (h2,p2)

So that

5.4/√1.44=h/√2.89

5.4/√1.44 ×√2.89 = h

7.65= h

h=7.65

8 0
1 year ago
A local cable company claims that the proportion of people who have Internet access is less than 63%. To test this claim, a rand
MaRussiya [10]

Answer:

Step-by-step explanation:

For the null hypothesis,

H0 : p = 0.63

For the alternative hypothesis,

Ha : p < 0.63

This is a left tailed test

Considering the population proportion, probability of success, p = 0.63

q = probability of failure = 1 - p

q = 1 - 0.63 = 0.37

Considering the sample,

Sample proportion, P = x/n

Where

x = number of success = 478

n = number of samples = 800

P = 478/800 = 0.6

We would determine the test statistic which is the z score

z = (P - p)/√pq/n

z = (0.6 - 0.63)/√(0.63 × 0.37)/800 = - 1.76

From the normal distribution table, the area below the test z score in the left tail 0.039

Thus

p = 0.039

7 0
1 year ago
the cost of an annual tuition at a university increased from 10,500 to 11,300 what is the percent increase in tuition to the nea
Maurinko [17]
Percent increase
find increase first
10500 to 11300
11300-10500=800
so
percent increase
change/original
origianal=10500
change=800
800/10500=8/105=0.0761
percent means parts out of 100
0.0761/1 times 100/100=7.61/100=7.61%

rond 7.61% to tenth or to 7.6%

7.6%

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2 years ago
An object is launched straight into the air. The projectile motion of the object can be modeled using h(t) = 96t – 16t2, where t
Vitek1552 [10]
In 7.56 mili sec the object will hit the ground
6 0
1 year ago
Read 2 more answers
A cement bridge post is 24 inches square and 15 feet 9 inches in length. If the cement weighs 145 pounds per cubic foot, how muc
lisov135 [29]

Answer:

The answer is option (C), One cement bridge post weighs 9,135 pounds

Step-by-step explanation:

Step 1: Get the total volume of a cement bridge post

The cement bridge post is in the shape of a cuboid, therefor the volume of the cement bridge post can be expressed as;

Volume of cement bridge post=Base area×Length

where;

Base area=(24^2) inches square

1 foot=12 inches

Convert 24 inches to foot=24/12=2^2=4 feet²

Length=15 feet and 9 inches

1 foot=12 inches

Convert 9 inches to foot=9/12=0.75 feet

Total length=(15+0.75)=15.75 feet

replacing;

Volume of cement bridge post=(4×15.75)=63 cubic feet

Volume of cement bridge post=63 cubic feet

Step 2: Get the total weight of the cement bridge post

Total weight of the cement bridge post=Weight per cubic foot×total volume of the cement bridge post

where;

Weight per cubic foot=145 pounds per cubic foot

Total volume of the cement bridge post=63 cubic feet

replacing;

Total weight of the cement bridge post=(145×63)=9,135 pounds

One cement bridge post weighs 9,135 pounds

8 0
1 year ago
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