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2 years ago

A sphere has a volume of 33.5 cubic inches. which value is closest to the radius of this sphere in inches?

Mathematics

1 answer:

EastWind [94]2 years ago

4 0

Radius = cube root (sphere volume * .75 / PI)radius = cube root (33.5 * .75 / PI)radius = cube root ( 7.9975358904)
radius =2 inches
Source: http://www.1728.org/diam.htm

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The following table contains data collected on the math averages of seniors in high school and their math averages as freshman i

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Where's the table?....

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2 years ago

The value of a rare painting has increased each year since it was found at a garage sale. The value of the painting is modeled b

solmaris [256]

799 represents the initial value of the painting

The painting will be worth $926 after 5 years to the nearest dollar

Step-by-step explanation:

The form of the exponential function is $f(x)=a(b)^{x}$ , where

a is the initial value ⇒ (at x = 0)
b is the growth/decay factor ⇒ (rate of change)
If b > 1, then the function is growth ⇒ (increasing)
If 0 < b < 1, then the function is decay ⇒ (decreasing)

The value of a rare painting has increased each year since it was

found at a garage sale

The value of the painting is modeled by the function $f(x)=799(1.03)^{x}$

We need to know what 799 represents and what the painting will

be worth after 5 years

∵ $f(x)=799(1.03)^{x}$

∵ The form of the function is $f(x)=a(b)^{x}$

- By comparing the two forms

∴ a = 799 and b = 1.03

∵ a is the initial value at x = 0

∴ 799 represents the initial value of the painting

∵ x represents the number of years

∴ x = 5

- Substitute the value of x in the function by 5

∵ $f(5)=799(1.03)^{5}$

∴ f(x) = 926.26

∴ The painting will be worth $926 after 5 years to the nearest dollar

799 represents the initial value of the painting

The painting will be worth $926 after 5 years to the nearest dollar

Learn more:

You can learn more about the functions in brainly.com/question/10382470

#LearnwithBrainly

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2 years ago

joyce is helping her aunt create craft kits. her aunt has 138 pipe cleaners, and each kit will include 6 pipe cleaners. what is

Andre45 [30]

23 pipe cleaners cause 23 x 6= 138

5 0

2 years ago

Read 2 more answers

What is 40653230000000 in standard form

lorasvet [3.4K]

4065323 × 10 to the senventh power?

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2 years ago

A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe

xxMikexx [17]

Answer:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

Step-by-step explanation:

For the random variable $N_1$ we define the possible values for this variable on this case $[1,2,3,4,5]$ . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

$5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10$

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable $N_1$ like this:

$P(N_1 = a) = \frac{5-a C 1}{5C2}$

For the distribution of $N_2$ we need to take in count that we are finding a conditional distribution. $N_2$ given $N_1 =a$ , for this case we see that $N_2 \in [1,2,...,5-a]$ , so then exist $5-a C 1$ ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

$P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}$

And if we want to find the joint probability we just need to do this:

$P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)$

And if we multiply the probabilities founded we got:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

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2 years ago