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2 years ago

A sphere has a volume of 33.5 cubic inches. which value is closest to the radius of this sphere in inches?

Mathematics

1 answer:

EastWind [94]2 years ago

4 0

Radius = cube root (sphere volume * .75 / PI)radius = cube root (33.5 * .75 / PI)radius = cube root ( 7.9975358904)
radius =2 inches
Source: http://www.1728.org/diam.htm

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A gallon of Moo Milk costs \$5.12$5.12dollar sign, 5, point, 12. What is the price, in dollars, of an 888 ounce glass of Moo Mil

Sladkaya [172]

The correct statement is:
A gallon of Moo Milk costs $5.12 What is the price, in dollars, of an 8 ounce glass of Moo Milk? There are 128 ounces in 1 gallon.

Solution:
Cost of 1 gallon of Moo Milk = $ 5.12

1 gallon = 128 ounces, so we can write:

Cost of 128 ounces of Moo Milk = $ 5.12

Cost of 1 ounce of Moo Milk = $ 5.12/128 = $ 0.04

Cost of 8 ounces of Moo Milk = $ 0.04 x 8 = $ 0.32

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3 0

2 years ago

Read 2 more answers

Josh travels frequently. For a particular airline, it takes 20 minutes for the first bag to arrive in baggage claim after a flig

Orlov [11]

Using the uniform distribution, it is found that:

A,B) 0.3 of the time does it take longer than 27 minutes for Josh’s bag to arrive in baggage claim.

C) 20% of the time does Josh’s bag arrive in less than 22 minutes.

--------------------------

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

$P(X < x) = \frac{x - a}{b - a}$

The probability of finding a value between c and d is:

$P(c \leq X \leq d) = \frac{d - c}{b - a}$

The probability of finding a value above x is:

$P(X > x) = \frac{b - x}{b - a}$

--------------------------

In the graph, we have that the distribution is uniform between 20 and 30 minutes, thus $a = 20, b = 30$

--------------------------

Itens a and b:

Above 27 minutes, thus:

$P(X > 27) = \frac{30 - 27}{30 - 20} = 0.3$

0.3 of the time does it take longer than 27 minutes for Josh’s bag to arrive in baggage claim.

--------------------------

Item c:

Less than 22 minutes, thus:

$P(X < 2) = \frac{22 - 20}{30 - 20} = 0.2$

0.2*100 = 20%

20% of the time does Josh’s bag arrive in less than 22 minutes.

A similar problem is given at brainly.com/question/15855314

6 0

1 year ago

The table shows data from Vicente's Form 1040. Gross income $75,000 Standard deduction $12,000 Taxable income $63,000 Total inco

Iteru [2.4K]

The answer is a+b+c = d it’s is equivalent to a and d

7 1

2 years ago

the weight of a bag of golf balls varies directly as the number of golf balls in the bag.If a bag of 69 gold balls weighs 2,553

seropon [69]

Answer: 30

Step-by-step explanation:

Given :The weight of a bag of golf balls varies directly as the number of golf balls in the bag.

Let x be the number of golf balls in a bag that weighs 1,110 grams.

Then we have the following direct variation equation,

$\dfrac{x}{1110}=\dfrac{69}{2553}$

Multiply 1110 both sides , we get

$x=\dfrac{69}{2553}\times1110=30$

Hence, there are 30 balls in the bag.

4 0

1 year ago

You are in a bike race. When you get to the first checkpoint, you are 25 of the distance to the second checkpoint. When you get

Rom4ik [11]

Question:

You are in a bike race. When you get to the first checkpoint, you are 2/5 of the distance to the second checkpoint. When you get to the second check point, you are 1/4 of the distance to the finish. If the entire race is 40 miles, what is the distance between the start and the first check point?

Answer: 4 miles

Step-by-step explanation:

Let distance between start to first checkpoint = x

First checkpoint to second checkpoint = 2/5 of x

Distance of start to checkpoint 1 = ( 2/5 of start to checkpoint 2)

Distance of start to checkpoint 2 = (1/4 of start to finish)

If start to checkpoint 2 = 1/4 of start to finish

Then,

Distance of start to checkpoint 1 = ( 2/5 * 1/4 of start to finish)

Distance of start to checkpoint 1 = 2/20 of start to finish = 1/10 of start to finish

Entire race = 40 miles = distance from start to finish

1/ 10 of 40

= ( 1/10) × 40

= 4 miles

6 0

2 years ago