Answer:
She subtracted the GCF from the second term in the expression instead of dividing.
Step-by-step explanation:
Given the expression 32ab-8b, to find the common greatest factor, we will bring out a function that us common to both terms 32ab and 8b. To do that, we need to first find their individual factors as shown:
32ab = (2×2×2)×2×2×a×(b)
8b = (2×2×2×b)
From both factors, the common terms are the values in parenthesis i.e 2×2×2×b = 8b
Hence the GCF of the expression 32ab - 8b is 8b. On factoring out 8b from the expression we will have;
= 32ab - 8b
= 8b(32ab/8b - 8b/8b)
= 8b(4a-1)
Comparing the gotten equation with Venita's own, 8b(4a-0), we can say that she correctly factored out the GCF but her error was that she subtracted 8b from the second term of the expression instead of dividing by 8b. 8b-8b is what gives her 0 making her expression wrong. She should have divided her second term also by 8b to have 8b/8b which results in 1 instead of 0 that venita got.
3t = 5(3-t)
3t = 15 - 5t
3t + 5t = 15
8t = 15
t = 15/8
t = 1 7/8
7/8 * 60 mins = 52.50 minutes
t = 1 hour and 52.5 minutes
It took Stu 1 hour and 52.5 minutes to hike the trail one way.
Answer:
The length of Michelle's forearm is 9 inches
Step-by-step explanation:
Remember that

To convert feet to inches, multiply by 12
we know that
The length of Michelle's forearm was 3/4 of a foot
Convert to inches
Multiply the length in feet by 12

therefore
The length of Michelle's forearm is 9 inches
<span><span><u>Answer</u>
26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.
<u>Explanation</u>
An integer is a whole number. It is a number that is not a fraction.
253/2=25+3/2=25+1 1/2=26 1/2
</span><span>26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.
</span></span>
We know that
Half-life is modeled by the formula
An=A0*(0.5)<span>^[t/h)]
where
An----------> </span>is the amount remaining after a time t
A0----------> is the initial quantity
t------------> is the time
h------------> is the half-life of the decaying quantity
in this problem
h=1601 years
A0=50 g
An=?
t=100 years
An=A0*(0.5)^[t/h)]---------> An=50*(0.5)^[100/1601)]-----> 47.88 gr
the answer is 47.88 g