Answer:
<h2>Option A is the answer(here the answer is calculated taking the whole value, without approximating it to a nearest value)</h2>
Step-by-step explanation:
Annual interest rate is 2.75%. Hence, the monthly interest rate is 
The amount will be compounded
times.
Every month they deposits $500.
In the first month that deposited $500 will be compounded 240 times.
It will be ![500\times [1 + \frac{2.75}{1200} ]^{240}](https://tex.z-dn.net/?f=500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B240%7D)
In the second month $500 will be deposited again, this time it will be compounded 239 times.
It will give ![500\times [1 + \frac{2.75}{1200} ]^{239}](https://tex.z-dn.net/?f=500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B239%7D)
Hence, the total after 20 years will be ![500\times [1 + \frac{2.75}{1200} ]^{240} + 500\times [1 + \frac{2.75}{1200} ]^{239} + ........+ 500\times [1 + \frac{2.75}{1200} ]^{1} = 160110.6741](https://tex.z-dn.net/?f=500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B240%7D%20%2B%20500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B239%7D%20%2B%20........%2B%20500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B1%7D%20%3D%20160110.6741)
1. Use a computer to randomly select 30 student IDs from all her students2. If the ice cream store owner asks 2300 people, will most likely pick cheesecake to be the flavor of the month.3. I would need the line plot4. I would need the graph to solve5. I would need the graph to solveClick to let others know, how helpful is it
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A = {1, 2, 5, 6, 8}
{1} U {2, 5, 6, 8}
{2} U {1, 5, 6, 8}
{5} U {1, 2, 6, 8}
{6} U {1, 2, 5, 8}
{8} U {1, 2, 5, 6}
{1, 2} U {5, 6, 8}
{1, 5} U {2, 6, 8}
{1, 6} U {2, 5, 8}
{1, 8} U {2, 5, 6}
{1, 2, 5} U {6, 8}
{1, 2, 6} U {5, 8}
{1, 2, 8} U {5, 6}
{1, 5, 6} U {2, 8}
{1, 5, 8} U {2, 6}
{1, 6, 8} U {2, 5}
The answer is 15 distinct pairs of disjoint non-empty subsets.
The answer is 1 because you are the only one in the garden. The rest of the people are in the yard.