If y = 3x and 2x – 4y = 3, then x=
2 answers:
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Answer:
B. 2
Step-by-step explanation:
a1,1=1
a1,2=2
a1,3=3
a2,1=4
a2,2=5
a2,3=6
a3,1=7
a3,2=8
a3,3=9
Answer:
So then P =11000 is the minimum that the least populated district could have.
Step-by-step explanation:
We have a big total of N = 132000 for the population.
And we know that we divide this population into 11 districts
And we have this info given "no district is to have a population that is more than 10 percent greater than the population of any other district"
Let's assume that P represent our minimum value for a district in the population. The range of possible values for the population of each district would be between P and 1.1 P
The interest on this case is find the minimum value for P and in order to do this we can assume that 1 district present the minimum and the other 10 the maximum value 1.1P in order to find which value of P satisfy this condition, and we have this:
So then P =11000 is the minimum that the least populated district could have.
Answer:
Step-by-step explanation:
(a)
Suppose we came up with an ideology whereby we pick a value for the length including the length dividing the inside into 4 parts(5 parallel sides), then we can get the value for breath by using the following process.
Let assume the length of the rectangle is 50;
Then, the breath can be calculated as follows:
= 50 × 5 = 250 ( since the breath is divided into 5 parallel sides)
The fencing is said to be 950 ft
So, 950 - 250 = 700
Then divided by 2, we get:
= 700/2
= 350
So for the first diagram; the length = 50 and the breath = 350
The area = 50 × 350 = 17500 ft²
Now, let's go up a little bit.
If the length increase to 100;
Then 100 × 5 = 500
⇒ 950 - 500 = 450
⇒ 450/2 = 225
The area = 225 × 100 = 22500 ft²
Suppose the length increases to 150
Then 150 × 5 = 750
⇒ 950 - 750 = 200
⇒ 200/2 = 100
The area = 150 × 100 = 15000 ft²
The diagrams for each of the outline above can be seen in the image attached below.
(b) The diagram illustrating the general solution can be seen in the second image provided below.
(c) The expression for the total area A in terms of both x and y is:
Area A = x×y
(d) Recall that:
The fencing is said to be 950 ft.
And the length is divided inside into 5 parallel sides;
Then:
5x + 2y = 950 (from the illustration in the second image below)
2y = 950 - 5x
(e)
From (c); replace the value of y in (d) into (c)
Then:
Area A = x×y
Open brackets
(f)
By differentiating what we have in (e)
x = 475/5
x = 95
From (d):
∴
Area A = x × y
Area A = 95 × 237.5
Area A = 22562.5 ft²
