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Bingel [31]
1 year ago
5

Find the 25th of sequence 3,5,7,9,11

Mathematics
1 answer:
zubka84 [21]1 year ago
5 0

Answer: The 25th term of the sequence is 75

Step-by-step explanation:

The given sequence depicts an arithmetic progression. The consecutive terms differ by a common difference. We will apply the formula for arithmetic progression.

Tn = a + (n-1)d

Tn = The value of the nth term of the arithmetic sequence.

a = first term of the sequence.

d = common difference (difference between a term and the consecutive term behind it)

n = number of terms in the sequence.

From the information given,

a = 3

d = 5-3 = 7-5 = 2

We want to look for the 25th term, T25

So n = 25

T25 = 3 + (25-1)2 = 3+ 24×2

T25 = 3 + 72 = 75

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Hope this is what you wanted.

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After simplifying, which expressions are equivalent? Select three options.
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Step-by-step explanation:

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Therefore, you get:

a.\ (3.4a - 1.7b) + (2.5a - 3.9b)=3.4a - 1.7b + 2.5a - 3.9b=5.9a-5.6b\\\\b.\ (2.5a + 1.6b) + (3.4a + 4b)=2.5a + 1.6b + 3.4a + 4b=5.9a+5.6b\\\\c.\ (-3.9b + a) + (-1.7b + 4.9a)=-3.9b + a -1.7b + 4.9a=5.9a-5.6b\\\\d.\ -0.4b +(6b - 5.9a)=-0.4b +6b - 5.9a=6b-6.3a\\\\e.\ 5.9a - 5.6b

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A force of 500.0 is represented graphically with its tail at the origin and the tip pointed in a direction 30.0° above the posit
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Answer:

F^{'}=(250\sqrt{3},250 })

Step-by-step explanation:

We have F´ =500 and \alpha=30º, so x and y components:

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