Question

A force of 500.0 is represented graphically with its tail at the origin and the tip pointed in a direction 30.0° above the positive x-axis. What are the x- and y-components of the vector?

Answer 1

Answer:

$F^{'}=(250\sqrt{3},250 })$

Step-by-step explanation:

We have F´ =500 and $\alpha$=30º, so x and y components:

F´ = $(F_{x} , F_{y})$ this is

$F_{x} = F^{'} *Cos\alpha$

$F_{y} = F^{'} *Sin\alpha$  

$F_{x} = F`*Cos\alpha =500*Cos30=500*\frac{\sqrt{3} }{2} =250\sqrt{3}$

$F_{y}=F*Sin\alpha =500*Sin30=500*\frac{1}{2}=250$;

Finally

F' = $(250\sqrt{3} , 250)$