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1 year ago

A room has an area of 121 ft2 but carpeting is only sold in m2. How much carpeting is needed to carpet the room?

Mathematics

2 answers:

stepladder [879]1 year ago

8 0

The correct answer is D. 11.24 m2

kykrilka [37]1 year ago

7 0

The correct answer for the question that is being presented above is this one: "D.)11.24 m2."
First, we need to know the conversion between feet to meters.
1 meter = 3.28 feet
1 meter^2 = 10.7584 ft^2

Given the value of 121 ft^2,
= 121 ft^2 * (1 m^2 / 10.7584 ft^2)
= 11.2470 m^2

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In a class of 20 students, 7 were wearing a white shirt. In the same class, 14 students had on blue jeans. Eyewitnesses all stat

nadezda [96]

Answer:

I want to answer 15%

Step-by-step explanation:

As for how to solve it I don't really know I would use process of elimination because the answer can't be so high that it's 45% so that's out. Personally I think that 35% is pretty high to so my best educated guess would be between 25% and 15% . Sorry this isn't more helpful.

6 0

2 years ago

Webassign find the area of the region bounded by the parabola y = x2, the tangent line to this parabola at the point (6, 36), an

Dvinal [7]

First find the tangent line

dy/dx=2x
at x=6, the slope is 2(6)=12
so
use point slope form
y-y1=m(x-x1)
point is (6,36)
so
y-36=12(x-6)
y-36=12x-72
y=12x-36

alright, so we know they intersect at x=6
and y=12x-36 is below y=x^2

so we do $\int\limits^6_0 {x^2} \, dx - \int\limits^6_0 {12x-36} \, dx = \int\limits^6_0 {x^2-(12x-36)} \, dx = \int\limits^6_0 {x^2-12x+36} \, dx =$
$[\frac{x^3}{3}-6x^2+36x]\limits^6_0=(\frac{6^3}{3}-6(6)^2+36(6))-(0)=\frac{216}{3}-216+216=$ $72+0=72$

the area under the curve bounded by the lines and the x axis is 72 square units

4 0

1 year ago

Find the measure of each acute angle.

crimeas [40]

The 3 inside angles of a triangle need to equal 180 degrees.

This is a right triangle so the bottom left corner is 90 degrees.

This means the other two angles when added need to equal 180-90 = 90 degrees.

Now you have 8x + 7x = 90

Combine like terms:

15x = 90

Divide both sides by 15

X = 6

Now you have the value for x solve the two angles:

8x = 8(6) = 48

7x = 7(6) = 42

Top left = 48 degrees

Bottom right = 42 degrees

8 0

1 year ago

Read 2 more answers

A score that is 6 points below the mean corresponds to a z-score of z = 22.00. What is the population standard deviation?

pochemuha

Answer:

<h2>Standard deviation is a measure of how spread out of numbers are:</h2>

Step-by-step explanation:

a score that is 6 points below the mean corresponds to a z score of z= 22 than the population standard deviation will be

----

z = (distance from mean)/(standard deviation)

-----

22 = 6/s

s = 6/22

s=0.272

The population standard deviation deviation is 0.272

4 0

1 year ago

One of your peers claims that boys do better in math classes than girls. Together you run two independent simple random samples

JulijaS [17]

Answer:

Step-by-step explanation:

Hello!

To test if boys are better in math classes than girls two random samples were taken:

Sample 1

X₁: score of a boy in calculus

n₁= 15

X[bar]₁= 82.3%

S₁= 5.6%

Sample 2

X₂: Score in the calculus of a girl

n₂= 12

X[bar]₂= 81.2%

S₂= 6.7%

To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.

To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.

Then you can calculate the interval as:

[(X[bar]_1-X[bar_2) ± $t_{n_1+n_2-2;1-\alpha /2}$ * $Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$ ]

$Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} } = \sqrt{\frac{14*(5.6^2)+11*(6.7^2)}{15+12-2} }= 6.108= 6.11$

$t_{n_1+n_2-2;1-\alpha /2}= t_{15+12-2;1-0.05}= t_{25;0.95}= 1.708$

[(82.3-81.2) ± 1.708* (6.11* $\sqrt{\frac{1}{15}+\frac{1}{12} }$ ]

[-2.94; 5.14]

Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.

I hope this helps!

3 0

2 years ago