Question

Solve for x in the equation x squared + 14 x + 17 = negative 96. x = negative 7 plus-or-minus 4 StartRoot 6 EndRoot i x = –7 ± 8i x = 7 plus-or-minus 4 StartRoot 6 EndRoot i x = 7 ± 8i

Answer 1

Answer:

$x=-7\pm8i$

Step-by-step explanation:

we have

$x^{2} +14x+17=-96$

Equate to zero

$x^{2} +14x+17+96=0$

$x^{2} +14x+113=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +14x+113=0$

so

$a=1\\b=14\\c=113$

substitute in the formula

$x=\frac{-14\pm\sqrt{14^{2}-4(1)(113)}} {2(1)}$

$x=\frac{-14\pm\sqrt{-256}} {2}$

Remember that

$i=\sqrt{-1}$

so

$x=\frac{-14\pm16i} {2}$

$x=-7\pm8i$

Answer 2

Answer:

its b on edge

Step-by-step explanation: