Find the geometric mean of 16 and 25. Round your answer to the nearest tenth

Seams Personal advertises on its website that 95% of customer orders are received within four working days. They performed an au

Bezzdna [24]

Answer:

a. Yes(n=500>=5, n(1-p)=25>=5)

b. 0.15241

Step-by-step explanation:

a. A normal approximation to the binomial can be used $n\geq$ 5 and n(1-p)>=5:

#We calculate our p as follows:

$\hat p$ =x/n=470/500=0.94

n=500

n(1-p)=500(1-0.95)=25

Hence, we can use the normal approximation.

b. This is a normal approximation.

-Given that p=0.95(95%)

-We verify if our distribution can be approximated to a normal:

$np=0.95\times 500=475\\n(1-p)=500(1-0.95)=25\\\\np\geq 5,\ n(1-p)\geq 5$

Hence, we can use the normal approximation of the form:

$P_{bin}(k,n,p)->N(\mu,\sigma^2)\left \{ {{\mu=np=475} \atop {\sigma=\sqrt{np(1-p)}=4.8734}} \right. \\\\\\P_{bin}(k\leq 470)\approx P_{norm}(x\leq 470.5)=P_{norm}(z\leq \frac{470-475}{4.8734})\\\\P_{norm}(z\leq -1.0260)=0.15241$

Hence, the probability of the sample proportion is the same as the proportion of the sample found is 0.15241

3 0

2 years ago

A CD usually sells for $17.00. If the CD is 30% off, and sales tax is 6%, what is the total price of the CD, including tax?

Ivan

If it is 30% off, then u r paying 70%

70% of 17 = 0.7(17) = 11.90 ...this is without tax

u have a tax rate of 6%.....

11.90 * 1.06 = 12.614 rounds to 12.61 <== total cost including tax

8 0

2 years ago

Read 2 more answers

In 1995, the total box office in U.S movie theaters was about $5.02 billion. From 1995 through 2008, the box office revenue incr

soldier1979 [14.2K]

Answer:

1.06 x $10^{10}$ (3sf)

Step-by-step explanation:

using compound interest formula A = P $(1+\frac{R}{100}) ^{n}$

from 95 to 08 is 13 yrs

Total Revenue = (5.02 x $10^{9}$ ) $(1 + \frac{5.9}{100}) ^{13}$ = 1.057 x $10^{10}$

6 0

2 years ago

HELP PLEASE I NEEED HELP!!!!

Nina [5.8K]

It is d just trust me

4 0

2 years ago

among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play

kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0

2 years ago