Answer:
The final pressure of the gas when its temperature returns to its initial value
Pa.
Step-by-step explanation:
Given : An ideal gas is confined within a closed cylinder at a pressure of
Pa by a piston. The piston moves until the volume of the gas is reduced to one-ninth of the initial volume.
To find : What is the final pressure of the gas when its temperature returns to its initial value?
Solution :
Since the temperature is constant
.
The relation between P and V is given by,

....(1)
The piston moves until the volume of the gas is reduced to one-ninth of the initial volume i.e. 
or 

Substitute in equation (1),
The final pressure of the gas when its temperature returns to its initial value
Pa.
For the answer to the question above, the opposite angles at the intersection of two straight lines as shown in the graph are congruent.
So the answer is simply∡ EIA and ∡ KIJ are congruent.
I hope my answer helped you. Have a nice day!
Solving this problem needs the distance formula of point to a line.
The formula is:
distance = | a x + b y + c | / √ (a^2 + b^2)
So we are given the equation: y = 2 x + 4
Rewriting this would be: y – 2 x – 4 = 0 -> a = -2, b = 1, c = -4
We are also given the points:
(-4, 11) = (x, y)
Plugging it in the distance formula at points (x, y):
distance = | -2 * -4 + 1 * 11 + -4 | / √ [(- 2)^2 + (1)^2]
= 15 / √ (5)
= 6.7
So the tree is approximately 6.7 feet away from the zip line.
Most likely, polygon <span>ABCD</span> has sides of known lengths.
It is also likely that one of the sides of polygon <span>EFGH</span> (not <span>EH</span>) is also known. For instance, its side <span>EF</span>.
If the above is true, we can find the scaling factor as a ratio between lengths of corresponding sides:
<span>r=<span><span>EF</span><span>AB</span></span></span>
Since this ratio is constant for any two corresponding lengths,
<span>r=<span><span>EH</span><span>AD</span></span></span>
From the last two equations we can derive:
<span>EH=AD⋅<span><span>EF</span><span>AB</span></span></span>
Hope That Helped : ) (Took a minute)
-502.5 - 115 = - 617.5
63 1/4 - 2 1/5 =
63 - 2 = 61
1/4 - 1/5 = 5/20 - 4/20 = 1/20
so 63 1/4 - 2 1/5 = 61 1/20
after the sub dove, elevation level is - 617.5 and temp is 61 1/20 F