All categories

2 years ago

Determine the slope of the line 3x − 5y − 6 = 0

Mathematics

2 answers:

Annette [7]2 years ago

5 0

Answer:

The slope is .6

Step-by-step explanation:

To find the slope of a line, we need the equation in slope/intercept form, y=mx+b. This means we need to isolate the y variable.

3x-5y-6=0

We can do this in one swoop by just adding 5y to the equation

+5y

3x-6=5y

now to get rid of that pesky 5, we can divide by 5.

.6x-1.2=y

Rearrange

y=.6x-1.2

The slope is .6, and the y intercept is -1.2.

ivolga24 [154]2 years ago

3 0

Answer:

slope 3/5

Step-by-step explanation:

3x − 5y − 6 = 0

To find the slope, we want to solve for y

(y = mx+b slope intercept form of the equation(

Add 5y to each side

3x − 5y+5y − 6 = 0+5y

3x-6 = 5y

Divide by 5

3/5x -6/5 = 5y/5

3/5 x -6/5 = y

The slope is 3/5 and the y intercept is -6/5

You might be interested in

How do i find each product by factoring the tens? 3x2, 3x20, and 3x200

RUDIKE [14]

Well, since it only asking about the product, you don't have to multiply the result
The product would be :
3 x 2 = 6
3x 20 = 3 x 2 x 10 = 60
3 x 200 = 3 x 2 x 10 x 10 = 600

hope this helps

6 0

2 years ago

Read 2 more answers

It is believed that as many as 23% of adults over 50 never graduated from high school. We wish to see if this percentage is the

JulijaS [17]

Answer:

1) n=48

2) n=298

3) n=426

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p$ represent the real population proportion of interest

$\hat p$ represent the estimated proportion for the sample

n is the sample size required (variable of interest)

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

Part 1

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.10$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.1$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume that the estimated proportion is 0.23 for the 25 to 30 group. And replacing into equation (b) the values from part a we got:

$n=\frac{0.23(1-0.23)}{(\frac{0.1}{1.64})^2}=47.63$

And rounded up we have that n=48

Part 2

The margin of error on this case changes to 0.04 so if we use the same formula but changing the value for ME we got:

$n=\frac{0.23(1-0.23)}{(\frac{0.04}{1.64})^2}=297.7$

And rounded up we have that n=298

Part 3

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: