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Sladkaya [172]
2 years ago
13

Think about all of the ways in which a circle and a parabola can intersect. Select all of the number of ways in which a circle a

nd a parabola can intersect.

Mathematics
2 answers:
tangare [24]2 years ago
8 0

Answer:

0

1

2

just sacrificed myself on edge

forsale [732]2 years ago
4 0

Answer:

A circle can intersect a parabola in

1. One point [ when circle just touches the parabola]

2. Two points [ When circle cuts the parabola in two distinct points. ]

3. Three points [Circle just touches at one point and cuts the parabola in two distinct points]

4. Four points [ Either parabola or circle meeting each other or crossing at four distinct points]




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Credit cards place a three-digit security code on the back of cards. What is the probability that a code starts with the number
ohaa [14]

Answer: 1/10

Step-by-step explanation: because there are 10 numbers (1,2,3,4,5,6,7,8,9, and 0)

7 0
2 years ago
Marine scientists have previously measured the weight of a wide-ranging fish to be 9.0 lbs with a standard deviation of 0.35 lbs
fenix001 [56]
Given:
Actual: 9.0 lbs with standard deviation of 0.35 lbs
sample: 8.2 lbs

standard deviation means that the fish caught should be within the range of  8.65 and 9.35

9.00 + 0.35 = 9.35 lbs
9.00 - 0.35 = 8.65 lbs

The sample that had an average weight of 8.2 lbs is not a representative of the population because its weight goes beyond the standard deviation. 
8 0
2 years ago
The area of a rectangular banquet call is 7400 ft.². The length of one side of the hall is 82 feet. Explain how you can use comp
kiruha [24]

Answer:

Compatible width of rectangular banquet hall could be 90 feet approximately.

Step-by-step explanation:

Given

Area of a rectangular banquet hall = 7400 square feet

Length of rectangular banquet hall = 82 feet

We need to calculate width of the rectangular banquet hall.

Now Area of rectangle is equal to length times width.

Framing in equation form we get;

Area\ of \ Rectangle= length \times width

Substituting the given values we get;

82 \times width = 7400\\\\width = \frac{7400}{82} = 90.2439

Now by definition of Compatible numbers which state that:

"Compatible numbers are the numbers that are easy to add, subtract, multiply, or divide mentally.  Compatible numbers are close in value to the actual numbers that make estimating the answer and computing problems easier."

Now By Using width as 90 feet and length as 82 feet we get area as 7380 sq ft. which is closet to actual area which is 7400 sq ft.

Hence we can say compatible width could be 90 feet approximately.

5 0
2 years ago
6.In a sample of 131 women with cosmetic dermatitis from using eye shadow, 12 were diagnosed with a nickel allergy. In a sample
aivan3 [116]

Answer:

a) 0.0916 - 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.0422

0.0916 + 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.1410

So then we can conclude that the true proportion of women with cosmetic dermatitis from using eye shadow at 95% of confidence is between (0.0422 and 0.1410)

b) \hat p = \frac{25}{250}= 0.1

0.1 - 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.0628

0.1 + 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.1372

So then we can conclude that the true proportion of women with cosmetic dermatitis from using mascara at 95% of confidence is between (0.0628 and 0.1372)

c) For this case we see that both confidence intervals contains the value of 0.12 so then we can't conclude that only one group is referenced at the significance level of 0.05 used.

Step-by-step explanation:

Part a

The estimated proportion of women with cosmetic dermatitis from using eye shadow is given by:

\hat p =\frac{12}{131}= 0.0916

The confidence  interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the proportion is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing we got:

0.0916 - 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.0422

0.0916 + 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.1410

So then we can conclude that the true proportion of women with cosmetic dermatitis from using eye shadow at 95% of confidence is between (0.0422 and 0.1410)

Part b: A 95% confidence interval for the women with cosmetic dermatitis from using mascara

\hat p = \frac{25}{250}= 0.1

0.1 - 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.0628

0.1 + 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.1372

So then we can conclude that the true proportion of women with cosmetic dermatitis from using mascara at 95% of confidence is between (0.0628 and 0.1372)

Part c: Suppose you are informed that the true proportion with a nickel allergy for one of the two groups (eye shadow or mascara) is .12. Can you determine which group is referenced? Explain.

For this case we see that both confidence intervals contains the value of 0.12 so then we can't conclude that only one group is referenced at the significance level of 0.05 used.

7 0
2 years ago
Rank the following quantities in order of decreasing volume. rank from highest to lowest volume. to rank items as equivalent, ov
Anastasy [175]
This should be the data:

1ML 
<span>100L </span>
<span>5 million nL </span>
<span>1GL </span>
<span>50 mL </span>
<span>1cL </span>
<span>1mL 
</span>
Below is the answer:

the conversion into litres are next to the order of volume. 
<span>1. 1GL (10^9) </span>
<span>2. 1ML (10^6) </span>
<span>3. 100L (100) </span>
<span>4. 50mL (50*10^-3)=0.05 </span>
<span>5. 1cL (10^-2) </span>
<span>6. 5 million nL [(5*10^6)*(10^-9)]=0.005 </span>
<span>7. 1mL (10^-3) </span>
5 0
2 years ago
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