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Paul [167]
1 year ago
12

One factor of the function f(x) = x3 − 8x2 + 17x − 10 is (x − 5). Describe how to find the x-intercepts and the y-intercept of t

he graph of f(x) without using technology. Show your work and include all intercepts in your answer.
Mathematics
2 answers:
Tasya [4]1 year ago
8 0

Answer:

x-intercepts: (1,0), (2,0), (5,0)

y-intercepts: (0,-10)

Step-by-step explanation:

kozerog [31]1 year ago
4 0

Answer:

x-intercepts: (1,0), (2,0), (5,0)

y-intercepts: (0,-10)

Step-by-step explanation:

One factor of the function f(x) = x^3-8x^2 + 17x-10 is (x-5).

Factor the polynomial in the following way:

x^3-8x^2 + 17x-10\\ \\=x^3-5x^2-3x^2+15x+2x-10\\ \\=x^2(x-5)-3x(x-5)+2(x-5)\\ \\=(x-5)(x^2-3x+2)

Now factor the quadratic in brackets:

x^2-3x+2\\ \\=x^2-2x-x+2\\ \\=x(x-2)-(x-2)\\ \\=(x-2)(x-1)

Hence,

f(x)=(x-5)(x-2)(x-1)

The x-intercepts are points at which y = 0, so

(x-5)(x-2)(x-1)=0\\ \\x-5=0\ \text{or}\ x-2=0\ \text{or}\ x-1=0\\ \\x=5\ \text{or}\ x=2\ \text{or}\ x=1

The y-intercepts are points at which x = 0, so

y=0^3-8\cdot 0^2+17\cdot 0-10=-10

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The summer after sophomore year, Haley nannied for a family and earned $2000. She
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You want to calculate the interest on $2000 at5.8% interest per month after six years?

Here is your formula: I =p*r*t

P is the principal amount which is $2000

R is the rate of interest which is 5.8% per month

T is the time involved whihc is six years  

You’re interest is 8352.00

3 0
1 year ago
A specimen of aluminum having a rectangular cross section 10 mm 12.7 mm (0.4 in. 0.5 in.) is pulled in tension with 35,500 N (80
miskamm [114]

Answer:

\epsilon = 3.958\times 10^{-3}

Step-by-step explanation:

The Young's Module of Aluminium is E = 69\times 10^{9}\,Pa. The axial stress on the specimen is:

\sigma = \frac{F}{A_{t}}

\sigma = \frac{35500\,N}{(0.01\,m)\cdot (0.013\,m)}

\sigma = 2.731\times 10^{8}\,Pa

The strain is derived of following expression:

\epsilon = \frac{\sigma}{E}

\epsilon = \frac{2.731\times 10^{8}\,Pa}{69\times 10^{9}\,Pa}

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4 0
2 years ago
Three highways connect city A with city B. Two highways connect city B with city C.
QveST [7]
(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:
0.992\times0.96=0.9523

(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:0.9984\times0.96=0.95846

β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:
0.992\times0.992=0.9841

Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:
P(A\cup B)=P(A)+P(B)-P(A\cap B)
0.9523+0.8-(0.9523\times0.8)=0.99
Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.


4 0
2 years ago
From home, Mary’s work is two thirds along the way to training. Training is 2.5km from work. Mary normally goes to work, then tr
polet [3.4K]
First thing to do is to illustrate the problem, Since it was mentioned that work was along the way to training, the order is shown in the picture. Mary's home and workplace are nearer compared to her training center. It is also mentioned that the distance between work and home, denoted as x, is 2/3 of the total distance from home to training. The total distance is (x + 2.5). Thus,

x = 2/3(x+2.5)
x = 2/3 x + 5/3
1/3 x = 5/3
x = 5 km

Thus, the distance from home to work is 5 km. This means that Mary has to walk this distance twice to return home to get her shoes. Then, she will travel again the total distance of 5+2.5 = 7.5 km to get to her training center. So,

Total distance = 2(5km) + 7.5 km
Total distance = 17.5 km

3 0
1 year ago
The value of zlatans house has increased by 7% his house is now valued at £749 000 work out the value of the house before the in
Colt1911 [192]

Answer:

Let x be the value of the house before increase

Since it's increases add 7% to the overall 100%

107/100x = 749000

x = 700000

The value of the house before increase is £700000.

Hope this helps.

4 0
2 years ago
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