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Paul [167]
2 years ago
12

One factor of the function f(x) = x3 − 8x2 + 17x − 10 is (x − 5). Describe how to find the x-intercepts and the y-intercept of t

he graph of f(x) without using technology. Show your work and include all intercepts in your answer.
Mathematics
2 answers:
Tasya [4]2 years ago
8 0

Answer:

x-intercepts: (1,0), (2,0), (5,0)

y-intercepts: (0,-10)

Step-by-step explanation:

kozerog [31]2 years ago
4 0

Answer:

x-intercepts: (1,0), (2,0), (5,0)

y-intercepts: (0,-10)

Step-by-step explanation:

One factor of the function f(x) = x^3-8x^2 + 17x-10 is (x-5).

Factor the polynomial in the following way:

x^3-8x^2 + 17x-10\\ \\=x^3-5x^2-3x^2+15x+2x-10\\ \\=x^2(x-5)-3x(x-5)+2(x-5)\\ \\=(x-5)(x^2-3x+2)

Now factor the quadratic in brackets:

x^2-3x+2\\ \\=x^2-2x-x+2\\ \\=x(x-2)-(x-2)\\ \\=(x-2)(x-1)

Hence,

f(x)=(x-5)(x-2)(x-1)

The x-intercepts are points at which y = 0, so

(x-5)(x-2)(x-1)=0\\ \\x-5=0\ \text{or}\ x-2=0\ \text{or}\ x-1=0\\ \\x=5\ \text{or}\ x=2\ \text{or}\ x=1

The y-intercepts are points at which x = 0, so

y=0^3-8\cdot 0^2+17\cdot 0-10=-10

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A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h
julsineya [31]

Answer:

a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

b. E(x) = 0.3

c. S(x)=0.5196

d. E=5,000

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\

For binomial distribution:

E(x)=np\\S(x)=\sqrt{np(1-p)}

Therefore, the company can expect to win 0.3 bids and it is calculated as:

E(x) = np = 3*0.1 = 0.3

Additionally, the standard deviation of the number of bids won is:

S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196

Finally, the probability to won 1, 2 or 3 bids is equal to:

P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001

So, the expected profit for the company is equal to:

E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

5 0
2 years ago
Which classification best describes the following system of equations? 3x+6y-12z=36 x=2y-4z=12 4x+8y-16z=48 inconsistent and dep
Viktor [21]

<u>Answer:</u>

Consistent and dependent

<u>Step-by-step explanation:</u>

We are given the following equation:

1. 3x+6y-12z=36

2. x+2y-4z=12

3. 4x+8y-16z=48

For equation 1 and 3, if we take out the common factor (3 and 4 respectively) out of it then we are left with x+2y-4z=12 which is the same as the equation number 2.

There is at least one set of the values for the unknowns that satisfies every equation in the system and since there is one solution for each of these equations, this system of equations is consistent and dependent.

6 0
1 year ago
Emma is planning her summer and would like to work enough to travel and buy a new laptop.
V125BC [204]
For the answer to the question above, <span>f x is the number of days she works, she'll earn $90x </span>
<span>After buying the laptop, she'll have $90x - $700 left over, which will pay for ($90x - $700) / $150 days of travel. So we have y = ($90x - $700) / $150 = (9x - 70) / 15 = 0.6x - (14/3) </span>
<span>Note that y can't be negative. Also, if y = 0, then Emma doesn't get to travel at all, so we should avoid that. So we have: </span>
<span>0.6x - (14/3) > 0 </span>
<span>0.6x > 14/3 </span>
<span>x > (14/3) / 0.6 </span>
<span>x > 70/9 </span>
<span>The question says that x can be up to 40, so the domain is 70/9 < x <= 40 </span>
<span>That's approximately 7.777... < x <= 40 </span>
<span>Multiply those numbers by 0.6 and then subtract 700 to get the range: </span>
<span>0 < y <= 58/3 </span>
<span>That's approximately 0 < y <= 19.333</span>
3 0
2 years ago
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Find the solution to each of these recurrence relations and initial conditions. use an iterative approach such as that used in e
Kamila [148]
Ok he anawee is d I’m pretty sure
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2 years ago
A dog's weight increased by 50% in 3 years. by the end of 3 years, the dog weighed 45 pounds. how much did the dog weigh 3 years
weeeeeb [17]
I hope this helps you



45+45.50%


45+45.50/100


45+22,5


67,5
6 0
2 years ago
Read 2 more answers
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