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Arte-miy333 [17]
2 years ago
7

Choose Yes or No to tell if the digit in the ones place is 1/10 the value of the digit in the tens place.

Mathematics
2 answers:
Zina [86]2 years ago
6 0

Answer:

4,099 and 5,011 are the numbers whose ones place is 1/10 the value of the digit in the tens place.

Step-by-step explanation:

1 : 4,099  - Yes, The digit at the ones place is 9 and the digit at the tens place is 90 (as per place value). So, 9 is one tenth of 90.

2 : 4,110  - No, the digit at ones place is zero and ones place is 10.

3 : 5,909  - No, the digit at ones place is 9 and digit at tens place is 0.

4 : 5,011 - Yes, the digit at ones place is 1 and the digit at tens place is 10. One tenth of 10 is 1.

Radda [10]2 years ago
5 0

Answer:

  • 4099 yes
  • 4110 no
  • 5909 no
  • 5011 yes

Step-by-step explanation:

The digits will be related by a factor of 10 if they are the same digit. 4099 and 5011 have the same digit in the tens and ones places. 4110 and 5909 do not.

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B. if lucinda has only $18 to spend and the price of kewpie dolls and the price of beanie babies are both $6, how many of each w
adoni [48]
Given the table below comparing the marginal benefit Lucinda gets from Kewpie dolls and Beanie Babies.

\begin{tabular}
{|p {2cm}|p {2cm}|p {2cm}|p {2cm}|}
\multicolumn {4} {|c|} {Lucinda's Kewpie Doll and Beanie Baby Marginal Benefits}\\[1ex]
\multicolumn {2} {|c|} {Kewpie Dolls}&\multicolumn {2} {|c|} {Beanie Babies}\\[1ex]
1&\$15.00&1&\$12.00\\
2&\$12.00&2&\$10.00\\
3&\$9.00&3&\$8.00\\
4&\$6.00&4&\$6.00\\
5&\$3.00&5&\$4.00\\
6&\$0.00&6&\$2.00\\
\end{tabular}

<span>If lucinda has only $18 to spend and the price of kewpie dolls and the price of beanie babies are both $6,

Lucinda will buy the combination for which marginal benefit is the same.

Therefore, Lucinda will buy </span><span>2 kewpie dolls and 1 beanie baby,</span><span> if she were rational.</span>

5 0
2 years ago
2 intersecting lines are shown. A line with point T, R, W intersects a line with points S, R, V at point R. Clockwise, from the
kolezko [41]

Answer:

Step-by-step explanation:

a) sum of angle on the straight line TRW is 180.

Given <TRS = 2x+10

<SRW = x-10

<TRS+<SRW = 180

2x+10+x-10 = 180

3x = 180

x = 180/3

x = 60°

<TRV = 180°-(2x+10)

Substitute x = 60° into the expression

<TRV = 180-(2(60)+10)

<TRV = 180-(120+10)

<TRV = 180-130

<TRV = 50°

2) From the diagram attached <MHJ= <LHK (oppositely directed angle)

Given

<MHJ= x+15

<LHK = 2x-20

Substitute the given data into the formula to get x

x+15= 2x-20

x-2x = -15-20

-x = -35

x = 35°

Next is to get the measure of <MHJ

<MHJ = x+15

<MHJ = 35+15

<MHJ = 50°

8 0
2 years ago
Carla packed this box with 1 centimeter cubes what is the volume of the box
shusha [124]

Answer: 60\ cm^3

Step-by-step explanation:

<h3> The complete exercise is attached.</h3>

You can observe in the picture attached that the box is a rectangular prism.

The volume of a rectangular prism can be found with this formula:

V=lwh

Where "l" is the length, "w" is the width and "h" is the height.

You know that the lenght of each side of those cubes is 1 centimeter. Therefore, you can multiply the number of cubes on each side of the box by 1 centimeter in order to find the lenght, the width and the height of the box:

 l=(4)(1\ cm)=4\ cm\\\\w=(3)(1\ cm)=3\ cm\\\\h=(5)(1\ cm)=5\ cm

Now you can substitute the lenght, the width and the height of the box into the formula shown at the beginning of the explanation:

V=(4\ cm)(3\ cm)(5\ cm)

Finally, evaluating, you get that the volume of the box is:

V=60\ cm^3

4 0
2 years ago
How do you simplify (25/a -a l) / (5+a)
andrey2020 [161]

Simplify the following:

(25/a - a l)/(a + 5)


Put each term in 25/a - a l over the common denominator a: 25/a - a l = 25/a - (a^2 l)/a:

(25/a - (a^2 l)/a)/(a + 5)

25/a - (a^2 l)/a = (25 - a^2 l)/a:

Answer: ((25 - a^2 l)/a)/(a + 5)

7 0
2 years ago
Which two equations would be most appropriately solved by using the zero product property? Select each correct answer.
LekaFEV [45]
The zero product property tells us that if the product of two or more factors is zero, then each one of these factors CAN be zero.

For more context let's look at the first equation in the problem that we can apply this to: (x-3)(x+4)=0

Through zero property we know that the factor (x-3) can be equal to zero as well as (x+4). This is because, even if only one of them is zero, the product will immediately be zero.

The zero product property is best applied to factorable quadratic equations in this case.

Another factorable equation would be 2x^{2}+6x=0 since we can factor out 2x and end up with 2x(x+3)=0. Now we'll end up with two factors, 2x and (x+3), which we can apply the zero product property to.

The rest of the options are not factorable thus the zero product property won't apply to them.
3 0
2 years ago
Read 2 more answers
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