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2 years ago

70x 6000 as commutative and associative properties

1 answer:

8 0

The commutative property of multuplication is that ab = ba. Therefore, 70 x 6000 = 6000 x 70. The associative of multiplication means the items can be regrouped without changing the answer: a(bc) = (ab)c. This means 70 x 6000 = 70 x 6 x 1000.

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What is the domain of validity for csctheta =start fraction 1 over sine theta end fraction? (1 point) all real numbers all real

dem82 [27]

We know the following relationship:

$csc(\theta)=\frac{1}{sin(\theta)}$

The domain of a function are the inputs of the function, that is, a function $f$ is a relation that assigns to each element $x$ in the set A exactly one element in the set B. The set A is the domain (or set of inputs) of the function and the set B contains the range (or set of outputs).Then applying this concept to our function $csc(\theta)$ we can write its domain as follows:

1. Domain of validity for $csc(\theta)$ :

$D: \{\theta \in R/ sin(\theta) \neq 0 \} \\ In words: All \ \theta \ that \ are \ real \ values \ except \ those \ that \ makes \ sin(\theta)=0$

When:

$sin(\theta)=0$ ?

when:

$\theta=..., -2\pi,-\pi,0,\pi,\2pi,3pi,...,k\pi$

where k is an integer either positive or negative. That is:

$sin(k\theta)=0 \ for \ k=...,-2,-1,0,1,2,3,...$

To match this with the choices above, the answer is:

"All real numbers except multiples of $\pi$ "


2. which identity is not used in the proof of the identity $1+cot^{2}(\theta)=csc^{2}(\theta)$ :

This identity can proved as follows:

$sin^2{\theta}+cos^{2}(\theta)=1 \ Dividing \ by \ sin^{2}(\theta) \\ \\ \therefore \frac{sin^2{\theta}}{sin^{2}(\theta)}+\frac{cos^{2}(\theta)}{sin^{2}(\theta)}=\frac{1}{sin^{2}(\theta)} \\ \\ \therefore 1+cot^{2}(\theta)=csc^{2}(\theta)$

The identity that is not used is as established in the statement above:

"1 +cos squared theta over sin squared theta= csc2theta"

Written in mathematical language as follows:

 $\frac{1+cos^{2}(\theta)}{sin^{2}(\theta)}=csc^{2}(\theta)$

4 0

2 years ago

Read 2 more answers

The Golden Braid Bookstore currently has $340,000 in cash, $280,000 in inventory, and $40,000 in accounts receivable. The compan

Ivenika [448]

Answer:

The quick ratio is 4.75:1.

Step-by-step explanation:

From the given information it is clear that:

Cash = $340,000

Inventory = $280,000

Accounts receivable = $40,000

Accounts payable = $65000

Other current liabilities = $15000

Formula for quick ratio:

$\text{Quick ratio}=\frac{\text{Cash + Current receivables + short-term investment}}{\text{Current Liabilities}}$

Substitute Cash = 340000, Current receivables=40000, Current Liabilities= (65000+15000).

$\text{Quick ratio}=\frac{340000+40000}{65000+15000}$

$\text{Quick ratio}=4.75$

Therefore the quick ratio is 4.75:1.

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2 years ago

Kaleb went to a theme park with $25 to spend. He spent $5.25 on food and paid $4.00 for each ride. What was the greatest number

Shtirlitz [24]

Answer is 4 rides
19.75 after food so divide it by 4 to get your answer

8 0

2 years ago

Solve this questions with steps

Alex_Xolod [135]

Provide better info thanks

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2 years ago

A taut string of length 10 inches is plucked at the center. The vibration travels along the string at a constant rate of c inche

Mademuasel [1]

Answer:

The correct option is

$A. \ \dfrac{1}{c} \times \left | x - 5 \right | = 0.3$

Step-by-step explanation:

The parameters given are;

The length of the string = 10 inches

The speed or rate of travel of the wave = c inches per millisecond

The position on the string from the left-most end = x

The time duration of motion of the vibration to reach x= 0.3 milliseconds

The distance covered = Speed × Time = c×0.3

Given that the string is plucked at the middle, with the vibration travelling in both directions, the point after 0.3 millisecond is x where we have;

The location on the string where it is plucked = center of the string = 10/2 = 5 inches

Distance from point of the string being plucked (the center of the string) to the left-most end = 5 inches

Therefore, on the left side of the center of the string we have;

The distance from the location of the vibration x (measured from the left most end) to the center of the string = 5 - x = -(x -5)

On the right side of the center, the distance from x is -(5 - x) = x - 5

Therefore, the the equation that can be used to find the location of the vibration after 0.3 milliseconds is $\dfrac{1}{c} \times \left | x - 5 \right | = 0.3$ or $\left | x - 5 \right | = 0.3 \times c$ which gives the correct option as A

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2 years ago