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Charra [1.4K]
2 years ago
12

You work for a landscaper that has a customer needing to seed an area of land 80 feet by 40 feet in size. The garden center has

5-pound bags of grass seed. Each bag of seed can cover 25 square yards of land. You calculate that the area you need to seed is 3200 square feet. You divide by 25 to find that you need 128 bags to seed the area. Is this correct?
Mathematics
2 answers:
Dovator [93]2 years ago
4 0

Answer:

No, the solution discussed in question is not correct.

Step-by-step explanation:

Length of the garden ,l= 80 feet

Breadth of the garden ,b= 40 feet

Area of the rectangle = l × b

Area of the garden = A

A=l\times b = 80 ft\times 40 ft = 3,200 ft^2

Area covered by 1 bag of seeds of grass = 25 yard^2=225 ft^2

1 yard^2 = 9 ft^2

Bags of seed of grass covering area of 3,200 ft^2:

\frac{3200 ft^2}{225 ft^2}=14.22

14.22 bags of seed of grass will occupy the area covered by the garden.

Andreas93 [3]2 years ago
3 0
You need to convert your 3200 sq ft into yards which is 355.556 sq yards then you divide 355.556 by 25 to get 14.22224 bags of seed needed
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Suppose that the duration of a particular type of criminal trial is known to be normally distributed with a mean of 21 days and
Black_prince [1.1K]

Answer:

0.33411

The probability that a particular criminal trial lasted atleast 24 days is 0.33411

Step-by-step explanation:

The random variable X is normally distributed with a mean of 21 and standard deviation of 7

;

X ~ N(μ = 21 ; σ = 7)

X ~ N(21, 7)

Probability that a trial lasted atleast 24 days :

P(X ≥ 24) :

The standardized score :

Z = (x - μ) / σ ; (24 - 21) / 7 ; 3 / 7 = 0.4286

Hence,

P(Z ≥ 0.4286) = 0.33411

The probability that a particular criminal trial lasted atleast 24 days is 0.33411

6 0
2 years ago
n 2018, homes in East Baton Rouge (EBR) Parish sold for an average of $239,000. You take a random sample of homes in Ascension p
Olenka [21]

Answer:

Conclusion

   There is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

Step-by-step explanation:

From the question we are told that

   The population mean for EBR is  \mu_ 1  = \$239,000

    The sample mean for Ascension parish  is \= x_2  = \$246,000

   The  p-value  is  p-value  =  0.045

     The level of significance is  \alpha = 0.01

The null hypothesis is  H_o : \mu_2  = \mu_1

The  alternative hypothesis is  H_a  :  \mu_2 > \mu_1

Here \mu_2 is the population mean for Ascension parish

   From the data given values we see that  

          p-value  >  \alpha

So we fail to reject the null hypothesis

So we conclude that there is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

3 0
2 years ago
Jamie has a collection of 78 nickels, dimes, and quarters worth $12.40. If the number of quarters is
vekshin1
Sorry idkis it 34.55? I’m slow-
3 0
2 years ago
Suppose a snow cone has a paper cone that is 8 centimeters deep and has a diameter of 5 centimeters. The flavored ice comes in a
Neko [114]

check the picture below.


so the cone itself has a height of 8, and a radius of 2.5, and the spherical scoop, ready to melt in it, has a radius of 2.5.


namely, will the volume of the sphere be larger than the cone? in which case the melted ice-cream will overflow.


\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=2.5\\ h=8 \end{cases}\implies V=\cfrac{\pi (2.5)^2(8)}{3}\implies \implies \boxed{V=\cfrac{50\pi }{3}} \\\\\\ \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\qquad r=2.5\implies V=\cfrac{4(\pi )(2.5)^3}{3}\implies \boxed{V=\cfrac{125\pi }{6}} \\\\\\ \textit{the sphere's volume is larger, so yes, it will overflow}

8 0
1 year ago
Read 2 more answers
The graph of f(x) = x6 – 2x4 – 5x2 + 6 is shown below.
DochEvi [55]

Answer:

There are two rational roots for f(x)

Step-by-step explanation:

We are given a function

f(x) = x^6-2x^4-5x^2+6

To find the number of rational roots for f(x).

Let us use remainder theorem that when

f(a) =0, (x-a) is a factor of f(x) or x=a is one solution.

Substitute 1 for x

f(1) = 1-2-5+6=0

Hence x=1 is one solution.

Let us try x=-1

f(-1) = 1-2-5+6 =0

So x =-1 is also a solution and x+1 is a factor

We can write f(x) by trial and error as

f(x) = (x-1)(x+1)(x^2-3)

We find that f(x) (x^2-3) factor gives two irrational solutions as

±√3.

Hence number of rational roots are 2.

5 0
1 year ago
Read 2 more answers
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