Ask question

Ask question

All categories

2 years ago

11

Use the expression (a+b)(c-d)+9e(a+b)(c−d)+9eleft parenthesis, a, plus, b, right parenthesis, left parenthesis, c, minus, d, rig

ht parenthesis, plus, 9, e to find an example of each kind of expression.
Kind of expression
Example

1 answer:

jek_recluse [69]2 years ago

8 0

Answer:

Difference: ¨c-d¨ variable: ¨a¨ coefficient: ¨9¨

Step-by-step explanation:

Just trust me bro

You might be interested in

A zookeeper is monitoring the population of birds. The flock needs to have exactly three times more females than males to thrive

KIM [24]

Answer:

The constraints are

$0 < x\leq 20$ and $0 < y\leq 60$

Step-by-step explanation:

Let

x ----> represent the number of male birds

y ----> represent the number of female birds

we know that

The flock needs to have exactly three times more females than males to thrive

so

$y=3x$ ----> equation A

The zoo only has room for a maximum of 20 male birds

so

$0 < x\leq 20$ ----> inequality B

we know that

The maximum number of male birds is 20

For x=20

substitute in the equation A

$y=3(20)=60$

so

The maximum number of female birds is 60

so

$0 < y\leq 60$ ----> inequality C

therefore

The constraints are

$0 < x\leq 20$ and $0 < y\leq 60$

4 0

2 years ago

A local concert center reports that it has been experiencing a 15% rate of no-shows on advanced reservations. Among 150 advanced

Doss [256]

Answer: C

Step-by-step explanation:

3 0

2 years ago

Al Johnson is a word processor. He is paid $2.95 a page. A normal job has 600 pages and requires about 225 words per page. About

mezya [45]

$2.95 * 600 pages= $1,770

D is the answer

7 0

2 years ago

Read 2 more answers

If G is midpoint of FH, find FG

pochemuha

The answer is 8 ihinghkki

8 0

2 years ago

The demand function for a type of portable radio is given by the model d=85−6x2, where d is measured in dollars and x is measure

Lostsunrise [7]

Answer:

Part A : The required Profit equation : $\text{Profit}= 60x-6x^3$

Part B : 0.303 million radios the profit became 18 million.

Part C : The graph is attached below.

Step-by-step explanation:

Given : The demand function for a type of portable radio is given by the model $d=85-6x^2$ , where d is measured in dollars and x is measured in millions of units. The production cost is $25.00 per radio.

Note: Given that profit = revenue - costs

Revenue is demand times number sold.

Costs are productions costs per number sold.

To find :

Part A: Write an equation giving profit as a function of x million radios sold.

Solution : Let x be the number of radios.

Revenue is demand times number sold

$\text{Revenue}= x\times (85-6x^2)$

$\text{Revenue}= 85x-6x^3$

Let the cost of x number of radios is 25x.

Profit = Revenue - Costs

$\text{Profit}= 85x-6x^3-25x$

$P(x)= 60x-6x^3$

The required Profit equation : $P(x)= 60x-6x^3$

Part B : The company currently produces 3 million radios and makes a profit of $18,000,000, but would like to scale back production. What lesser number of radios could the company produce to yield the same profit?

Solution : It is shown graphically which is attached in part c

When we scale back production we get that,

When we sold 0.303 million radios the profit became 18 million.

Part C : Give a graph for the profit and label the parts of the graph.

The graph is attached below which shows the profitable radios points.

3 0

2 years ago